Answer:
y > 1/3 x - 3
Step-by-step explanation:
First, it would be easiest to find the equation of the line from the two integer points given, which are (0, -3) and (3, -2).
Find the change of y over the change of x to get the slope of the line.
(-2 - (-3))/(3 - 0) = 1/3
Since the line intercepts the y axis at (0, -3), the equation of the line would be
y = 1/3x - 3
We can see that the shaded portion is above the line, (and that the line is dotted) so this graph represents
<u>y > 1/3 x - 3</u>
Answer:
Step-by-step explanation:
yes i think so
Step-by-step explanation: last year
Answer:
The ship is located at (3,5)
Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III
Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II
To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.
Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9
We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3
Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5
Based on the above, the position of the ship is (3,5).
Hope this helps :)
Answer:
Step-by-step explanation:
As per given information there are 18000 CCTV cameras in the area of 783.8 square kilometers
To find the average number of cameras you divide the number by the area.
The average number of CCTV cameras per square kilometer in NYC = 18000/783.8 = 22.9650421026 ≈ 23
It should be rounded up if taking approximate number
Yes you can have as many equal signs as you need and the approximately equal sign in the same equation.
