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Fantom [35]
2 years ago
12

Define potential difference in a uniform electric field?

Physics
1 answer:
8090 [49]2 years ago
6 0

Explanation:

For example, a uniform electric field E is produced by placing a potential difference (or voltage) ΔV across two parallel metal plates, labeled A and B. ... The relationship between ΔV and E is revealed by calculating the work done by the force in moving a charge from point A to point B.

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One difference between a hypothesis and a theory is that a hypothesis
DaniilM [7]

A hypothesis is a proposed explanation made on the basis of limited information while a theory is a series of ideas intended to explain something.

7 0
2 years ago
An unknown fluid has a specific gravity of 0.750. What is the volume of 22.5 kg of this fluid?
Andru [333]
<h2>Option C is the correct answer.</h2>

Explanation:

Specific gravity of fluid = 0.750

Density of fluid = Specific gravity of fluid x Density of water

Density of fluid = 0.750 x 1000

Density of fluid = 750 kg/m³

Mass of fluid = 22.5 kg

We have

         Mass = Volume x Density

         22.5 = Volume x 750

         Volume = 0.03 m³ = 30 L

Option C is the correct answer.

5 0
2 years ago
Which of the following is the only requirement for an object to be in projectile motion? A. The horizontal and vertical motions
NARA [144]
The answer is d, gravity is the only force acting on the object
8 0
3 years ago
Explain whether a tennis ball dropped from a high distance experiences an elastic collision or inelastic collision
hodyreva [135]
I need help on that too poop head
4 0
2 years ago
A 1500 kg car, initially traveling at 22.0 m/s, hits its brakes and skids to a stop. Determine the work done by friction.
Sedbober [7]

Answer:

<em>The work done by the car is 363 kJ</em>

Explanation:

Work : Work is said to be done when a Force moves an object through a certain distance. Work and Energy are interchangeable because they have the same unit. The unit of work is Joules (J).

Mathematically work done can be expressed as,

E = W = 1/2mv²

W =  1/2mv²................................ Equation 1

Where E = Energy, W = work done, m = mass of the car, v = velocity of the car

<em>Given: m=1500 kg, v=22 m/s</em>

<em>Substituting these values into equation 1</em>

<em>W = 1/2(1500)(22)²</em>

<em>W = 750 × 484</em>

<em>W = 363000 J</em>

<em>W = 363 kJ</em>

<em>Thus the work done by the car is 363 kJ</em>

8 0
2 years ago
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