The equivalent resistance of the two cylindrical conductors connected in parallel is 466 ohm.
<h3>
Resistance</h3>
Resistance is a measure of the opposition to flow of electric current. It is measured in ohms.
It is given by the formula:

Given that R₂ = 469 ohm, hence:

But l₁ = 6l₂, r₁ = (1/5)r₂, hence:
![R_1=\rho \frac{l_1}{A_1}=\rho *\frac{6l_2}{[\pi (1/5)r_2]^2} =150 * \rho \frac{l_2}{[\pi r_2]^2}=30*469=70350\ ohm](https://tex.z-dn.net/?f=R_1%3D%5Crho%20%5Cfrac%7Bl_1%7D%7BA_1%7D%3D%5Crho%20%2A%5Cfrac%7B6l_2%7D%7B%5B%5Cpi%20%281%2F5%29r_2%5D%5E2%7D%20%3D150%20%2A%20%5Crho%20%5Cfrac%7Bl_2%7D%7B%5B%5Cpi%20r_2%5D%5E2%7D%3D30%2A469%3D70350%5C%20ohm)
The equivalent resistance (R) is:

The equivalent resistance of the two cylindrical conductors connected in parallel is 466 ohm.
Find out more on resistance at: brainly.com/question/17563681
Answer:
<em>The total time is: t=451.22 sec</em>
<em>The average speed is: V=34.57 m/s</em>
Explanation:
<u>Average speed</u>
The average speed is calculated by dividing the total distance traveled by an object (x) by the total time it took it to travel that distance (t).

Since the student makes the trip in two parts, we have to calculate the total distance and the total time.
We know the distance to school is 7.8 Km = 7,800 m. The student makes his way home over the same distance, thus the total distance is
x=2*7,800 m=15,600 m
The first trip to school was done at an average speed of v1=32.6 m/s. Knowing the distance and speed, we can calculate the time:

The second trip back home was done at an average speed of v2=36.8 m/s. Let's calculate the second time:

The total time is:


The average speed is:


Answer:
C. Dark Matter
Explanation:
Dark matter is estimated to make up 90 percent of the mass of the galaxy.
The dark matter (as astronomers have come to call the invisible material) extends to a distance of at least 200,000 light-years from the center of the Galaxy.
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