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HACTEHA [7]
3 years ago
11

A ball is thrown upward. what is its initial vertical speed? the acceleration of gravity is 9.8 m/s 2 and maximum height is 4.1

m ,. neglect air resistance. answer in units of m/s
Physics
1 answer:
sergij07 [2.7K]3 years ago
6 0

the question is missing another parameter. we need to know the time taken for the ball to come down. You can use the below formula to find the initial vertical speed.

S = 1/2at2 + ut

distance = 1/2 × acceleration × time2 + intial speed × time
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harmful effects

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A force of 30 N stretches a very light ideal spring 0.73 m from equilibrium. What is the force constant (spring constant) of the
pantera1 [17]

Answer:

Explanation:

F = k*n

F = 30N

k = ???

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A gold ball has a mass of 45g. In a speed test, a golf ball was driven from rest to a velocity of 90m/s.
Andrew [12]

Answer:

1)

Acceleration (a)=change in velocity/ change in time

Velocity (v)=90m/s

Time=0.0005s

a=90/0.0005

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Force = mass x acceleration

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F= 7200N or 7.2kN

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7 0
3 years ago
If the car's speed decreases at a constant rate from 77 mi/h to 50 mi/h in 3.0 s, what is the magnitude of its acceleration, ass
Lostsunrise [7]

The acceleration of the car,

a = \frac{v-u}{t}

Here, v is final velocity, u is initial velocity and t is time taken by the car.

Given u =77 \ mil/h ,v = 50 mi/h and t = 3.0 s = 3.0 \times \frac{1 \ h}{3600} = 8.3 \times 10^{-4} h

Therefore, from above equation

a =  \frac{50 \ mi/h -77 \ mi/h}{8.33 \times 10^{-4} h} = - \frac{27 \ mi/h }{8.33 \times 10^{-4} h} = - 3.2 \times 10^{4} \ mi/h^2.

Here, negative sign shows deceleration of a car.

Thus the the magnitude of car acceleration is 3.2 \times 10^{4} \ mi/h^2.

3 0
3 years ago
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