To solve this problem it is necessary to apply the concepts related to the flow as a function of the volume in a certain time, as well as the potential and kinetic energy that act on the pump and the fluid.
The work done would be defined as
Where,
PE = Potential Energy
KE = Kinetic Energy
Where,
m = Mass
g = Gravitational energy
h = Height
v = Velocity
Considering power as the change of energy as a function of time we will then have to
The rate of mass flow is,
Where,
= Density of water
A = Area of the hose 
The given radius is 0.83cm or 
m, so the Area would be
We have then that,
Final the power of the pump would be,
Therefore the power of the pump is 57.11W
Answer:
C. Add all the force vectors
Explanation:
The net force acting on an object is the vector sum of all the forces on the object.
Remember, Newton's first law tells us a body at rest will remain at rest or that in uniform motion will continue in motion unless acted by unbalanced forces.These unbalanced forces act in all direction towards the body thus to get the net force you require a summation of all these force with respect to their magnitudes and directions.
For example a force of 3N towards the East direction acting on a body and another force of 2N towards the West direction on the same body will generate a net force of 1N towards the East direction.
Answer:
10 watts
Explanation:
first calculate work.
Work =force×distance cos thita
10Kg×0.50M cos 0= 5joules
Therefore, Power=Work÷ Time
Therefore, 5joules÷0.50s=10 watts.
