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Bond [772]
2 years ago
10

PLEASE NO LINKS DONT WASTE YOUR TIME IM NOT GONNA CLICK. What are the zeros of this function?

Mathematics
1 answer:
Artyom0805 [142]2 years ago
8 0

Answer: C. x = 4 and x = 6

Step-by-step explanation:

Zeros of a function would be the value of x when f(x) is 0.

Based on the given graph, the parabola has 2 locations where the y-value is 0 and the graph hits the x-axis.

The graph hits the x-axis at 4 and at 6.

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1. Y=-2×+4<br> Complete the missing value in the solution to the equation (____,-2)
Ipatiy [6.2K]

Answer:

x =2

Step-by-step explanation:

y = - 2 x + 4

0 = - 2 x + 4

x = 2

6 0
3 years ago
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Which ordered pair is a solution of the equation?
frozen [14]
It’s B because 5 = -3(-3) - 4
5=9-4
Just plug in the numbers and see what works
3 0
2 years ago
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Help me do this …math
Daniel [21]

Step-by-step explanation:

How to find inverse function:

Step 1: Write down equation.

f(x) = 4 \sin(x)  + 3

Remeber Ruler notation that

f(x)=y so we replace y with f(x).

y = 4 \sin(x)  + 3

Next, we must isolate x so first we subtract 3.

y - 3 = 4 \sin(x)

Divide both sides by 4.

\frac{y - 3}{4}  =  \sin(x)

\sin {}^{ - 1} ( \frac{y - 3}{4} )  =  \sin {}^{ - 1} ( \sin(x) )

Remeber that sin^-1x and sin x are inverse functions so they will cancel out to x. So we get

\sin {}^{ - 1} ( \frac{y - 3}{4} )  = x

Swap x and y. So our inverse function is

\sin {}^{ - 1} ( \frac{x - 3}{4} )  = y

If you want another proof: Here's one,

Let plug an a x value for the orginal equation,

4 sin x+3. Let say that

x =  \frac{\pi}{2}

We then would get

4 \sin( \frac{\pi}{2 } )  + 3 = 4 \times (1) + 3 = 4 + 3 = 7

So when x=pi/2, y=7.

By definition of a inverse function, if we let 7 be our input, we should get pi/2. as a output.

So let see.

\sin {}^{ - 1} ( \frac{7 - 3}{4} )  =  \sin {}^{ - 1} ( \frac{4}{4} )  =  \sin {}^{ - 1} (1)  =  \frac{\pi}{2}

So this is the inverse function of 4 sin x+3.

1b. The range of f(x) is [-1,7).

We can use transformations to describe range.

We have

f(x) = 4 \sin(x)  + 3

Parent function is

\sin(x)

with a range of [-1,1].

We then vertical stretch by 4 so we get

4 \sin(x)

and our range will be

[-4,4].

Then we add a vertical shift of 3.

4 \sin(x)  + 3

So our range of 4 sin x+3.

[-1,7].

1c. Domain of a inverse function is the range of the orginal function.

The range of f(x) is [-1,7) so the domain of f^-1(x) is [-1,7].

f(x) domain was restricted to -pi/2 to pi/2 so the range of f^-1(x) is [-pi/2, pi/2]

6 0
2 years ago
PLEASE HELP!! this is due today! I will mark the brainliest!
densk [106]

Answer:

the answer is C

Step-by-step explanation:

4 0
3 years ago
What are the solution(s) to the quadratic equation 50 – x2 = 0? x = ±2 x = ±6 x = ±5 no real solution btw i just clicked the las
bagirrra123 [75]
50-x^2=0
Move the x^2 to the other side
x^2=50
Now take the square root of both sides
x=+_(50)^1/2 (^1/2 means square root)(+_ is plus or minus. Sorry XD)
Now simplify the square root
X=+_5(2)^1/2
Voila. The answer is C
3 0
2 years ago
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