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3 years ago

PLS HELP FOR TEST DUE IN A HOUR

Chemistry

1 answer:

Lorico [155]3 years ago

8 0

Answer:

9.9L

Explanation:

Using the general gas law constant;

PV = nRT

Where;

P = pressure (atm)

V = volume (litres)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

According to the information provided in this question; P = 1.20 atm, V = ?, T = 15°C = 15 + 273 = 288K, n = 0.5mol

Hence, using PV = nRT

V = nRT/P

V = 0.5 × 0.0821 × 288/1.20

V = 11.8224/1.2

V = 9.853

Volume = 9.9L

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lions [1.4K]

Answer:

The percentage error in the measurement is 2.4% 

Explanation:

The measurement made by the student is $0.966 g/cm^3$ .

But the actual value of density is $0.943 g/cm^3$

The formula to calculate percentage error is

percentage error = $\frac{(measured \ value-actual \ value)}{(actual \ value)} \times 100$

Hence percentage error in this case is given by

Percentage error = $\frac{(0.966-0.943)}{0.943} \times 100$

= $\frac{0.023}{0.943} \times 100=2.4%$

A physical quantities value will be determines by various quantities. If errors are made in measuring any of these quantities there will be error in the measurement of the final physical quantity as well.

Here density of a substance is a derived quantity determined by measuring mass and volume of that substance. If errors are made in mass and volume measurements the density value will also be erroneous.

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3 years ago

12 G of carbon react with 16 G of oxygen how much carbon monoxide is formed

elena55 [62]

Answer:

28 g CO

Explanation:

First convert grams to moles.

1 mole C = 12.011 g (I'm just going to round to 12 for the sake of this problem)

12 g C • $\frac{1 mol C}{12 g C}$ = 1 mol C

1 mol O = 15.996 g (I'm just going to round to 16)

16 g O • $\frac{1 mol O}{16 g O}$ = 1 mol O

So the unbalanced equation is:

$C + O_{2}$ -> $CO$ (the oxygen has a 2 subscript because it is part of HONClBrIF meaning when not in a compound these elements appear in pairs - called diatomic elements)

The balanced equation is:

$2 C + O_2$ -> $2 CO$

However, carbon is the limiting reactant in this equation and two moles cannot react because only 12 g (1 mole) are present. Therefore, use the equation

$C + \frac{1}{2} O_2$ -> $CO$ .

1 mole of CO is formed, therefore 12 g + 16 g = 28 g CO.

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3 years ago

Describe the activities to prove that Liquid exerts pressure equally and perpendicularly in all direction

Vlad1618 [11]

Step by step explanation
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2.mark points on the bottle in any level four directions perpendicularly
3.make a hole in the points you have marked
Observation
The liquid exerts pressure equally and perpendicularly in all directions

Hope this answer helps

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3 years ago

We add 1.4 moles to 700 mL of water. What is the molarity

Nastasia [14]

Answer:

Molarity= 2M

Explanation:

n=1.4, V= 700ml= 0.7dm3

n= CV

1.4= C×0.7

C= 1.4/0.7= 2M

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4 years ago

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