Ask question

Ask question

All categories

3 years ago

11

What is x-16>-35 what is x

1 answer:

maxonik [38]3 years ago

3 0

Answer:

To me, it seems like x can have multiple values.

Step-by-step explanation:

First of all, you could say, x = 17. After all, 17 - 16 equals 1, which is greater than negative 35. You could also say x = -18. After all, -18 minus 16 would equal to -34, which is greater than -35.

Now, if the problem is asking for a number that is the <u>closest to -35</u> and <u>greater than it</u>--then I would say x = -18.

You might be interested in

Point A is located at (−5, 2) on a coordinate grid. Point A is translated 4 units to the right and 2 units down to create point

love history [14]

Answer:C) 4.5 units

Step-by-step explanation:

4 0

3 years ago

A fruitshake costs R2,00 more than a chocolate milkshake. If 3 fruitshakes and 5 chocolate milkshakes cost R78,00, determine the

kvv77 [185]

Step-by-step explanation:

Let F represent fruitshake and C chocolate milkshake

one fruitshake cost more 2R more than chocolate shake and

3F + 5C = R78,00

Then (78 - 6) ÷ 8 = 9

a fruitshake costs R11,00 and chocolate milkshake costs 9R,00

3 0

3 years ago

Read 2 more answers

If x(f) = x5 and g(x) = -2-3x2 , which is f(g(x))

mel-nik [20]

At least 20 characters long

5 0

3 years ago

Louis was saving money to purchase a remote-controlled model airplane. The plane cost $48. His grandfather gave him $6 and his m

Ira Lisetskai [31]

Answer:

yes louis would have enough money

Step-by-step explanation:

3 0

4 years ago

Read 2 more answers

What are the roots of 3x2 + 10 = 4x?

sveticcg [70]

Answer:

Option C is correct.

roots of the given equation , $x =\frac{2\pm i\sqrt{26}}{3}$

Step-by-step explanation:

Given the equation: $3x^2+10 = 4x$

We can write this equation as:

$3x^2-4x + 10 =0$

A quadratic equation is in the form of $ax^2+bx+c =0$ ......[1] where a,b ,c are the coefficient and x is the variable,

the solution of the equation is given by;

$x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

On comparing given equation with equation [1] we get;

a = 3 , b = -4 and c =10

So, the solution of the given equation is given by;

$x = \frac{-(-4)\pm\sqrt{(-4)^2-4(3)(10)}}{2(3)}$

or

$x = \frac{4\pm\sqrt{(16-120}}{6} = \frac{4\pm\sqrt{(-104)}}{6} = \frac{4\pm\sqrt{(-4 \times 26)}}{6}$

or

$x =\frac{4\pm2 \sqrt{(-26)}}{6} = \frac{4\pm2 i\sqrt{26}}{6}$ [∴ $\sqrt{-1} = i$

Simplify:

$x =\frac{2\pm i\sqrt{26}}{3}$

therefore, the roots of the given equation are; $x =\frac{2\pm i\sqrt{26}}{3}$

5 0

3 years ago

Read 2 more answers