Answer:
{x,y} = {5,6}
Step-by-step explanation:
// Solve equation [1] for the variable x
[1] x = y - 1
// Plug this in for variable x in equation [2]
[2] 2•(y -1) - y = 4
[2] y = 6
// Solve equation [2] for the variable y
[2] y = 6
// By now we know this much :
x = y-1
y = 6
// Use the y value to solve for x
x = (6)-1 = 5
Answer:
sin(theta) + cos(theta) = 0
sin(theta) = -cos(theta)
sin(theta)/cos(theta) = -1
tan(theta) = -1
theta = - 45° ± k·180°
Answer: m=−3
Step-by-step explanation: −40−2(3m+1/2)=7m−2
−40+(−2)(3m)+(−2)(1/2)=7m+−2
−40+−6m+−1=7m+−2
(−6m)+(−40+−1)=7m−2
−6m+−41=7m−2
−6m−41−7m=7m−2−7m
−13m−41+41=−2+41
−13m/−13=39/−13
m=−3
What mistake I guess Keith did make is he subtracted 2 from -39 which equaled to -37 which caused him divide -37 by 13 when it should have been 39 divided by 13 because he should have left 39 alone and not have subtracted 2 from it also it should not have been negative basically what I'm trying to say is that he did his division and subtraction wrong.
Take the vector u = <ux, uy> = <4, 3>.
Find the magnitude of u:
||u|| = sqrt[ (ux)^2 + (uy)^2]
||u|| = sqrt[ 4^2 + 3^2 ]
||u|| = sqrt[ 16 + 9 ]
||u|| = sqrt[ 25 ]
||u|| = 5
To find the unit vector in the direction of u, and also with the same sign, just divide each coordinate of u by ||u||. So the vector you are looking for is
u/||u||
u * (1/||u||)
= <4, 3> * (1/5)
= <4/5, 3/5>
and there it is.
Writing it in component form:
= (4/5) * i + (3/5) * j
I hope this helps. =)
Answer:
2
Step-by-step explanation:
