All categories

3 years ago

Write the slope-intercept form of the equation of the line 3x - 2y = -16

1 answer:

5 0

We will solve for y.
$-3x-16=-2y$

Divide both sides by -2
$y=\frac{3}{2}x + 8$

<u>Slope-intercept form</u>
$y=\frac{3}{2}x + 8$

You might be interested in

Exactamente a las 6:45 am mi reloj se daño y comenzo a caminar en sentido contrario a la velocidad correcta, ahora son las 9:30

garri49 [273]

Answer:

El reloj está marcando:

las 4:00 horas

Step-by-step explanation:

El reloj avanzó a su mismo ritmo pero en sentido contrario a partir de las 6:45

si ahora son las 9:30 el reloj marca:

9:30 = 9horas 30minutos = 9h 30'

6:45 = 6horas 45minutos = 6h 45´

1 hora = 60'

9h 30' = 8h + 60' + 30' = 8h + 90' = 8h 90'

entonces:

8h 90'

- 6h 45'

= 2h 45

entonces el reloj está marcando 2h 45' menos que la hora en que se dañó.

por tanto:

6h 45'

- 2h 45'

= 4h 00'

El reloj ahora está marcando las

4 horas en punto.

7 0

3 years ago

I need help with this math question

algol13

Third option. The letter has neither rotate or symmetry

8 0

3 years ago

Find the y value at the point x = -2.

Wewaii [24]

By looking at the graph, we can visually determine that the value of y when point x = -2 is <u>-4.</u>

5 0

3 years ago

Read 2 more answers

What is a point-slope equation of the line with slope -10 that goes through the point (1,4)

KatRina [158]

$\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad \qquad \qquad 
% slope = m
slope = m\implies -10
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-4=-10(x-1)$

8 0

3 years ago

Read 2 more answers

Determine if triangle ABC with coordinates A (0, 2), B (2, 5), and C (−1, 7) is an isosceles triangle. Use evidence to support y

kirill115 [55]

Answer:

The triangle ABC is an isosceles right triangle

Step-by-step explanation:

we have

The coordinates of triangle ABC are

A (0, 2), B (2, 5), and C (−1, 7)

we know that

An isosceles triangle has two equal sides and two equal internal angles

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

substitute in the formula

$d=\sqrt{(5-2)^{2}+(2-0)^{2}}$

$d=\sqrt{(3)^{2}+(2)^{2}}$

$dAB=\sqrt{13}\ units$

step 2

Find the distance BC

substitute in the formula

$d=\sqrt{(7-5)^{2}+(-1-2)^{2}}$

$d=\sqrt{(2)^{2}+(-3)^{2}}$

$dBC=\sqrt{13}\ units$

step 3

Find the distance AC

substitute in the formula

$d=\sqrt{(7-2)^{2}+(-1-0)^{2}}$

$d=\sqrt{(5)^{2}+(-1)^{2}}$

$dAC=\sqrt{26}\ units$

step 4

Compare the length sides

$dAB=\sqrt{13}\ units$

$dBC=\sqrt{13}\ units$

$dAC=\sqrt{26}\ units$

$dAB=dBC$

therefore

Is an isosceles triangle

Applying the Pythagoras Theorem

$(AC)^{2} =(AB)^{2}+(BC)^{2}$

substitute

$(\sqrt{26})^{2} =(\sqrt{13})^{2}+(\sqrt{13})^{2}$

$26=13+13$

$26=26$ -----> is true

therefore

Is an isosceles right triangle

8 0

3 years ago