If freshwater is added to a region, what happens to seawater density and salinity?

Chemistry

1 answer:

azamat3 years ago

7 0

Answer:

The density and salinity goes down.

Explanation:

Salt water is denser than pure water. As fresh water is added to salt water the concentration of salt goes down. Since salinity is the amount of salt in the water that would go down with the concentration. This would also mean that the density goes down since there is less salt per unit of volume which makes it so that there is less mass per unit of volume. The formula for density is d=m/v so as the mass goes down per unit of volume so does the density.

Let me know if anything is unclear in the comments and we can try to work through it.

You might be interested in

A gas is contained in a thick-walled balloon. When the pressure change from 100 kPa to 90.0 kPa, the volume changes from 2.50 L

Orlov [11]

The temperature change is calculated using the combined gas law
that is P1V1/T1 =P2V2/T2
P1= 100KPa
P2=90kpa
v1= 2.50 L
v2= 3.75 L
T1= 303 K
T2=?

T2 is therefore = P2V2T1/P1V1
=( 90 x 3.75 x303)/ (100 x2.50) = 409.05 K

3 0

3 years ago

Read 2 more answers

QUESTION 21 The combustion of ammonia in the presence of excess oxygen yields NO 2 and H 2O: 4 NH 3 (g) 7 O 2 (g) 4 NO 2 (g) 6 H

Harrizon [31]

Answer:

The answer to your question is 47.44 g of Oxygen

Explanation:

Data

mass of Ammonia = 14.4 g

mass of Oxygen = ?

Balanced chemical reaction

4NH₃ + 7O₂ ⇒ 4NO₂ + 6H₂O

Process

1.- Calculate the molar mass of Ammonia

NH₃ = 4[(1 x 14) + (3 x 1)] = 4[14 + 3] = 4[17] = 68 g

2.- Calculate the molar mass of Oxygen

O₂ = 7[16 x 2] = 7[32] = 224 g

3.- Use proportions to calculate the mass of Oxygen

68g of NH₃ --------------------- 224 g of O₂

14.4 g of NH₃ ----------------- x

x = (14.4 x 224) / 68

x = 3225.6/ 68

x = 47.44 g

5 0

3 years ago

the temperature of a balloon rises from 275 degrees k to 395 degrees k, what would the ending volume be if it started at 5 L

Airida [17]

<h3>Answer:</h3>

7.182K

<h3>Explanation:</h3>

From the question we are given;

Initial temperature, T1 = 275 K
Final temperature, T2 = 395 K
Initial volume, V1 = 5 L

We are required to calculate the final volume, V2

Charles's law is the law that relates the volume of a gas and its temperature.
It states that the volume of a fixed mass of a gas and its absolute temperature are directly proportional at a constant pressure.
Therefore;

$\frac{V1}{T1}=\frac{V2}{T2}$