Question

An aqueous potassium chloride, KCl, solution is made by dissolving 0.295 0.295 mol KCl in 740.0 740.0 g of water. Calculate the molality of the solution.

Answer 1

Answer:

Molality is 0.40 m

Explanation:

Molality is a sort of concentration that indicates the moles of solute dissolved in 1kg of solvent.

To determine molality we need the moles of solute, and the mass of solvent in kg so:

We convert the mass of solvent from g to kg:

740 g . 1kg/1000g = 0.740 kg

We know the moles, so we can determine molality

Molality (mol/kg) = 0.295 mol/ 0.740kg = 0.40 m

Answer 2

Answer:

Molality of the solution = 0.399 molal

Explanation:

Step 1: Data given

Number of moles KCl = 0.295 moles

Mass of water = 740.0 grams

Step 2: Convert mass to kg

740 grams = 740 *10^-3 kg = 0.740 kg

Step 3: Calculate the molality of the solution

Molality of the solution = moles KCl / mass water

Molality of the solution = 0.295 moles / 0.740 kg

Molality of the solution = 0.399 mol /kg = 0.399 molal