<span>-3(5+8r)=33-8r
-15 - 24r = 33 - 8r
-15 - 33 = - 8r + 24r
-48 = 16r
-48/16 = r
-3 = r
r = -3</span>
Answer:
The amount of acid in third container is =42%
Step-by-step explanation:
Given , one container is filled with a mixture that is 30% acid a second container filled with a mixture that is 50% acid and the second container 50% larger than the first .
Let, the volume of first container is = x
Then , the volume of second container = (x+ x of 50%)
= x + 0.5 x
= 1.5 x
Therefore the amount of acid in first container
= 0.3 x
The amount of acid in second container
= 0.75x
Total amount of acid= 0.3x + 0.75x = 1.05 x
Total amount of solution = x+1.5x = 2.5x
The amount of acid in third container is =
%
= 42%
Answer:
The Answer is D
Step-by-step explanation:
All you do is add both equations 3^x+10x+2x-4
then you add the like varibles which is 10x+2x=12x
So, the answer is 3^x+12x-4
(0,-6), (6, -3), and (6,-6)
If you plot them on a graph there are only two point options (in green and purple) since it's a right triangle but you have to use the one that has -6 as the y value
Answer:
No solution
Step-by-step explanation:
