1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Scilla [17]
3 years ago
5

17 cm 12 cm 5 cm pls help

Mathematics
1 answer:
miskamm [114]3 years ago
7 0

Answer:

30 cm²

Step-by-step explanation:

A = bh/2

A = (12 cm)(5 cm)/2

A = 30 cm²

You might be interested in
Gabrielle is 12 years younger than Mikhail. The sum of their ages is 76 . What is Mikhail's age?
Over [174]

Answer:

48 years old

Step-by-step explanation:

Let x = Mikhail's age

then x-15 = Gabrielle's age

x + x-15 = 81

2x-15 = 81

2x = 96

x = 48 years old

6 0
3 years ago
Read 2 more answers
The U.S. Department of Education reported that in 2007, 67% of students enrolled in college or a trade school within 12 months o
MrRissso [65]

Answer:

a) The 90% confidence interval is 0.575\leq \pi\leq 0.701

b) The margin of error is 0.063.

Step-by-step explanation:

We have to construct a 90% confidence interval for the proportion of students enrolled in college or a trade school within 12 months of graduating from high school in 2013.

We have a sample of 160 students, and a proportion of:

p=X/N=102/160=0.6375

The standard deviation is:

\sigma=\sqrt{\frac{p(1-p)}{N}}=\sqrt{\frac{0.6375*0.3625}{160}}=0.038

As the sample size is big enough, we use the z-value as statistic. For a 90% CI, the z-value is z=1.645.

Then, the margin of error is:

E=z\cdot\sigma=1.645\cdot 0.038=0.063

Then, the 90% confidence interval is:

p-z\cdot \sigma\leq \pi\leq p+z\cdot\sigma\\\\0.638-0.063\leq \pi\leq 0.638+0.063\\\\0.575\leq \pi\leq 0.701

4 0
3 years ago
The answer is in red but I need someone to show the work PLEASE ?!
trapecia [35]

Answer:

(-1, -8)

Step-by-step explanation:

So you would do the simplifying by "subtracting" the equations from each other. So to isolate the x, you could subtract the y away.

   8x + y = -16

  -3x + y = -5

-___________

11x = -11

x = -1

Then, substitute x into either equation.

8(-1) + y = -16

-8 + y = -16

Isolate y.

y = -8

3 0
3 years ago
An elevator in an office building made the following moves: Up 7 floors, down 14 floors, up 6 floors, down 2 floors, up 9 floors
kolezko [41]

Answer:

It started on the 55th floor.

Step-by-step explanation:

We can work backwards from the 54th floor. Since we are working <em>backwards</em>, if the elevator goes up, we will subtract and if it goes down, we will add. Starting with 54, we get 54 + 5 = 59, then 59 - 9 = 50, then 50 + 2 = 52, then 52 - 6 = 48, then 48 + 14 = 62, then 62 - 7 = 55.

8 0
3 years ago
PLEASE HELP DUE TOMORROW WILL GIVE BRAINLIEST
olya-2409 [2.1K]

Answer:

y=-2x+18

Step-by-step explanation:

so, we use the format y=mx+b where m and b are numbers. b=18, and m=-2, since he SPENDS 2 dollars each day. y=-2x+18 would be your answer. remember, b is also the y intercept, so one of the points that would work would be (0, 18) and the x intercept would be when y is zero, aka  0=-2x+18 which we can solve to get (9,0)

6 0
3 years ago
Other questions:
  • What does 3/216 simplify to
    8·1 answer
  • What is the inverse of f(x)=2x^3
    10·1 answer
  • Classify the function as a linear or quadratic and identify the quadratic, linear, and constant terms. y=(3x+4)(-2x-3)
    9·1 answer
  • What are not multiples of 4?
    12·2 answers
  • joanna split three pitchers of water equally among her eight plants.what fraction of a pitcher did each plant get?
    14·1 answer
  • What is the x-coordinate of the solution to the system?
    7·1 answer
  • Find an equation that is equivalent to 2x+3y=6 in polar cordintates
    8·1 answer
  • Slope pls help ASAP due tonight
    13·2 answers
  • Midpoint of (-6, 3) and (8, -7)
    10·1 answer
  • Which type of function is shown in the table below?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!