Solve the equation by completing the square s^2+2s-6=0

Mathematics

1 answer:

Valentin [98]3 years ago

4 0

Answer:

s=√7-1

s=-(√7+1)

Step-by-step explanation:

s^2+2s-6=0

or,s^2+2.s.1+1^2=6+1^2

or,(s+1)^2=6+1

or,(s+1)^2=7

or,(s+1)^2=(±√7)^2

or,s+1=±√7

either,

s=√7-1

or,

s=-(√7+1)

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Composition of functions occurs when we have two functions normally written similar or exactly like f(x) & g(x) - you can have any coefficients to the (x), but the most commonly seen are f(x) and g(x). They are written as either f(g(x)) or (f o g)(x). Because our composition is written as $(f \circ g)(2)$ , we are replacing the x values in the g(x) function with 2 and simplifying the expression.

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Now, because we are composing the functions, this value we have solved for now replaces the x-values in the f(x) function. So, f(x) becomes f(6), and we use the same manner as above to simplify.

$f(6) = (6)^2-2$