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posledela
3 years ago
10

Fill in the blanks below in order to justify whether or not the mapping shown represents a function

Mathematics
2 answers:
kipiarov [429]3 years ago
7 0

Answer:

Step-by-step explanation:

Set A:

-2

2

3

-4

Set B:

1

6

-1

**** -2 goes with 6

2 goes with -1

3 goes with 1

-4 goes with1

g100num [7]3 years ago
3 0

Answer:

kk 12

Step-by-step explanation:

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Express the sum of each pair of numbers as a product of greatest common factor of the numbers and another sum
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Say the pair of numbers are expressed by a*g and b*g, with g being their greatest common factor, their sum, a*g+b*g = g*(a+b)
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at a school concert the total value of tickets sold was $994. Student tickets sold for $5 and adult tickets sold for $8. The num
ValentinkaMS [17]

Answer:

42 student tickets and 98 adult tickets

Step-by-step explanation:

Let's call the number of student tickets 's' and the number of adult tickets 'a'.

Then, we can write the two equations below:

5s + 8a = 994

a = 2s + 14

Using the value of 'a' from the second equation in the first one, we have:

5s + 8*(2s + 14) = 994

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4 years ago
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Which system of equations represents the matrix shown below?
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D

Step-by-step explanation:

just compare the augmented matrix to the possible answers and you will see it the option D

4 0
4 years ago
A new post-surgical treatment is being compared with a standard treatment. Seven subjects receive the new treatment, while seven
a_sh-v [17]

Answer:

(17.714-28.714) -2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -19.745

(17.714-28.714) +2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -2.255

Step-by-step explanation:

For this case we have the following info given:

Treatment: 12 13 15 19 20 21 24

Control: 18 23 24 30 32 35 39

We can find the sample mean and deviations with the the following formulas:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

s =\sqrt{\frac{\sum_{i=1}^n (X_i- \bar X)^2}{n-1}}

And repaplacing we got:

\bar X_T = 17.714 the sample mean for treatment

\bar X_C = 28.714 the sample mean for treatment

s_T= 4.461 the sample deviation for treatment

s_C= 7.387 the sample deviation for control

n_T= n_C= 7 the sample size for each sample

The degrees of freedom are given by:

df= 7+7-2= 12

The confidence interval for the difference of means is given by:

(\bar X_T -\bar X_C) \pm t_{\alpha/2} \sqrt{\frac{s^2_T}{n_T} +\frac{s^2_C}{n_C}}

The confidence is 98% so then the significance is \alpha=0.02 and \alpha/2 =0.01. Then the critical value would be:

t_{\alpha/2}=2.681

And replacing we got:

(17.714-28.714) -2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -19.745

(17.714-28.714) +2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -2.255

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4 years ago
I really don’t understand year 7 algerbra
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Answer:

same here

Step-by-step explanation:

idekhshdhdhrhryryryrue

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3 years ago
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