Answer:
The chord is bisected.
Step-by-step explanation:
see the attached figure to better understand the problem
In the circle of the figure
The diameter is the segment DE
The chord is the segment AB
PA=PB=r ----> radius of the circle
Triangles PAC and PBC are congruent right triangles by SSS
Because
PA=PB
PC is a common side
AC=BC ----> Applying Pythagoras Theorem
therefore
The chord AB is bisected
Answer:
Your answer is going to be one of the 1/3 I'm pretty sure it is the positive 1/3 because the line is not decreasing.
Step-by-step explanation:
Google helps to so try that
Answer:
b = √(c^2 - a²)
Step-by-step explanation:
Start with the given c = √a^2 + b^2. Squaring both sides, we get:
c² = a² + b².
We want to iosolate b² and then b.
So: subtract a² from both sides, resulting in:
c² - a² = b²
Taking the square root of both sides, we get:
√b² = √(c² - a²)
and so:
b = √(c^2 - a²)
A right angles is 90 degrees
if you mean 5/4 of the MEASURE of a right angle then
90 times 5/4 (because in math 'of' means multiply)
90 tmes 5/4=450/4=225/2=112.5 degrees
