<h3>hello!</h3>
=====================================================
Parallel lines have the same slope.
So if the given line has a slope of 3, then the line parallel to it has the same slope (3)
Now, let's write the equation of the line in Point-Slope Form.
Remember, point-slope form looks like so:-
Where
y₁ is the y-coordinate of the point that the line passes through
m is the slope
x₁ is the x-coordinate of the point that the line passes through
In this case,
y₁ is equal to -8
m is equal to 3
x₁ is equal to 1
Plug in the values:
Simplify:
and we're done!
=========================================================
<h3>note:-</h3>
Hope everything is clear; if you need any more explanation/clarification, kindly let me know, and I will comment and/or edit my answer :)
Answer:
i think X^3y^12
Step-by-step explanation:
.......
Answer:
B. 15 m^3
Step-by-step explanation:
The volume of a rectangular prism is the product ...
V = lwh
For the given values of l, w, h, the volume is ...
V = (5 m)(1 m)(3 m) = 15 m^3
Answer:
Step-by-step explanation:
In my opinion you look really pretty already, but I would say just to go for it! What have you go to lose. If you do choose to do it good luck, I’m sure it will look good.
(And if someone you think is your friend says something rude or drops you, then just remember that means they aren’t a true friend)
<span> Let x = the width
Let 2x = the length
Let h = the height
</span>then vol = x*2x*h. So we have 2x^2*h = 24
h=24/(2*x^2)=12/x^2
Surface area: two ends + 1 bottom + 2 sides (no top)
S.A. = 2(x*h) + 1(2x*x) + 2(2x*h)
S.A. = 2xh + 2x^2 + 4xh<span> S.A. = 2x^2 + 6xh
</span>Replace h with 12/x^2
S.A = 2x^2 + 6x(12/x^2)
S.A = 2x^2 + 6(12/x)
S.A = 2x^2 + (72/x)
Graph this equation to find the value of x for minimum material
Min surface area when x = 3.0 is the width<span> then
</span>2(3) = 6 is the length
Find the height:
h=12/(3.0)^2
h=1.33
Box dimensions for min surface area: 3.0 by 6 by 1.33; much better numbers
Check the vol of these dimensions: 3.0*6*1.33 ~ 24
graphic attachment
