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dmitriy555 [2]
3 years ago
7

I neeedddd help. I am not understanding. Can someone help?/ explain this?

Mathematics
1 answer:
zysi [14]3 years ago
8 0

Answer:

F= 4 4/6

Step-by-step explanation:

Lets break it down

3 1/6 + f - 7 5/6

3 plus what equals 7 answer 4!

1/6 pls how many more sixths equals 5/6th answer 4/6 ths

so overall you combine the two answers for whole and fraction an

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Given f(x), find g(x) and h(x) such that f(x)=g(h(x)) and neither g(x) nor h(x) is solely x. f(x)=−3x+4⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√3+5
iVinArrow [24]

Answer:

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Step-by-step explanation:

Consider the given function is

f(x)=\sqrt[3]{-2x+4}-5

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f(x)=\sqrt[3]{(-2x+4)}-5

Let h(x)=-2x+4, then we get

f(x)=g(h(x))=\sqrt[3]{h(x)}-5

Substitute h(x)=x in the above function.

g(x)=\sqrt[3]{x}-5

Therefore, the required functions are h(x)=-2x+4 and g(x)=\sqrt[3]{x}-5.

Check the solutions.

g(h(x))=g(-2x+4)             [\because h(x)=-2x+4]

g(h(x))=\sqrt[3]{-2x+4}-5            [\because g(x)=\sqrt[3]{x}-5]

g(h(x))=f(x)

Therefore, our solution is correct.

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