3 years ago

The difference of two integers is 5. Twice the smaller integer is 8 more than the larger integer. What are the two integers?

1 answer:

3 0

Answer:

18 and 13

Step-by-step explanation:

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Inga [223]

Answer:

D is the correct answer

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Oksanka [162]

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Step-by-step explanation:

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galben [10]

Answer:

B. 1/(3xy^3)

Step-by-step explanation:

The minus sign can be dealt with first, then the root taken.

$\left(9x^{2}y^{6}\right)^{-\frac{1}{2}}=\dfrac{1}{\sqrt{9x^{2}y^{6}}}\\\\=\dfrac{1}{\sqrt{9}\sqrt{x^2}\sqrt{y^6}}=\dfrac{1}{3xy^3}$

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Len [333]

1792=3x+14
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3 years ago

The difference of two integers is 5. Twice the smaller integer is 8 more than the larger integer. What are the two integers?​