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3 years ago

A hamburger and a soda cost $1.45. Two hamburgers and one soda cost $2.50. What is the price of one soda?

Mathematics

2 answers:

Rom4ik [11]3 years ago

7 0

Price of one soda is B , 0.40
x+y=1.45
2x+y=2.5

Solve simultaneous equation for y
You will get 0.4

Natasha_Volkova [10]3 years ago

7 0

Answer:

$0.40

Step-by-step explanation:

let a hamburger be X and soda b y

then X + Y is equals to 1.45

2 X + Y is equals to 2.50

using elimination method we will fine the value of x

2 X + Y = 2.50

- X + Y= 1.45

X = 1.05

now how to find the value of Y

we know that X + Y = 1.45

putting the value of x

we get Y is equals to 1.45-1.05

$0.40

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The computers of nine engineers at a certain company are to be replaced. Four of the engineers have selected laptops and the oth

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Answer:

(a) There are 70 different ways set up 4 computers out of 8.

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Step-by-step explanation:

Of the 9 new computers 4 are laptops and 5 are desktop.

Let X = a laptop is selected and Y = a desktop is selected.

The probability of selecting a laptop is = $P(Laptop) = p_{X} = \frac{4}{9}$

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Then both X and Y follows Binomial distribution.

$X\sim Bin(9, \frac{4}{9})\\ Y\sim Bin(9, \frac{5}{9})$

The probability function of a binomial distribution is:

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(a)

Combination is used to determine the number of ways to select k objects from n distinct objects without replacement.

It is denotes as: ${n\choose k}=\frac{n!}{k!(n-k)!}$

In this case 4 computers are to selected of 8 to be set up. Since there cannot be replacement, i.e. we cannot set up one computer twice or thrice, use combinations to determine the number of ways to set up 4 computers of 8.

The number of ways to set up 4 computers of 8 is:

${8\choose 4}=\frac{8!}{4!(8-4)!}\\=\frac{8!}{4!\times 4!} \\=70$