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Serggg [28]
3 years ago
7

Each cube in this rectangular prism is 1 cm3.What is the volume of the rectangular prism?

Mathematics
1 answer:
Lelechka [254]3 years ago
4 0

Answer:

Volume of rectangular prism = 20\ cm^3

Step-by-step explanation:

Given rectangular prism is made up of small cubes of volume 1 cubic centimeter.

To find volume of rectangular prism.

Solution:

Volume of rectangular prism is = length\times width \times height

We know that all sides of a cube are equal in measure.

So, we will count the number of cubes on each side to get the exact measure.

Length side = 4 cubes = 5 cm

Width side = 2 cubes = 2 cm

Height side = 2 cubes = 2 cm

Thus volume of rectangular prism =  5\ cm\times 2\ cm \times 2\ cm

Volume of rectangular prism = 20\ cm^3

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In this question, it is necessary to first check all the details that are already provided in the question. Then after they are noted down the final thing required is to find the answer to the question by correct calculations.
Distance for which the truck traveled = 280 kilometers
Time taken to travel the given distance = 4 hours.
Then
Speed of the truck = Distance traveled/Time taken
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 5/4=y−1/4<br><br>y=_____<br>What is the answer?
Nat2105 [25]

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A random sample of 500 registered voters in Phoenix is asked if they favor the use of oxygenated fuels year-round to reduce air
Stells [14]

Answer:

a) 0.0853

b) 0.0000

Step-by-step explanation:

Parameters given stated that;

H₀ : <em>p = </em>0.6

H₁ : <em>p  = </em>0.6, this explains the acceptance region as;

p° ≤ \frac{315}{500}=0.63 and the region region as p°>0.63 (where p° is known as the sample proportion)

a).

the probability of type I error if exactly 60% is calculated as :

∝ = P (Reject H₀ | H₀ is true)

   = P (p°>0.63 | p=0.6)

where p° is represented as <em>pI</em><em> </em>in the subsequent calculated steps below

   

    = P  [\frac{p°-p}{\sqrt{\frac{p(1-p)}{n}}} >\frac{0.63-p}{\sqrt{\frac{p(1-p)}{n}}} |p=0.6]

    = P  [\frac{p°-0.6}{\sqrt{\frac{0.6(1-0.6)}{500}}} >\frac{0.63-0.6}{\sqrt{\frac{0.6(1-0.6)}{500}}} ]

    = P   [Z>\frac{0.63-0.6}{\sqrt{\frac{0.6(1-0.6)}{500} } } ]

    = P   [Z > 1.37]

    = 1 - P   [Z ≤ 1.37]

    = 1 - Ф (1.37)

    = 1 - 0.914657 ( from Cumulative Standard Normal Distribution Table)

    ≅ 0.0853

b)

The probability of Type II error β is stated as:

β = P (Accept H₀ | H₁ is true)

  = P [p° ≤ 0.63 | p = 0.75]

where p° is represented as <em>pI</em><em> </em>in the subsequent calculated steps below

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  = P [\frac{p°-0.6} \sqrt{\frac{0.75(1-0.75)}{500} } }\leq \frac{0.63-0.75}{\sqrt{\frac{0.75(1-0.75)}{500} } } ]

  = P[Z\leq\frac{0.63-0.75}{\sqrt{\frac{0.75(1-0.75)}{500} } } ]

  = P [Z ≤ -6.20]

  = Ф (-6.20)

  ≅ 0.0000 (from Cumulative Standard Normal Distribution Table).

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Answer:

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