Distribution with a mean of 100 and standard deviation of 15...

1 answer:

8 0

Use the z-score:
112 - 100
For 112, the z-score is --------------- = 12/15, or 0.8.
15

Next, find the AREA under the standard normal curve TO THE LEFT OF 0.8.

Use either a z-score table or a calculator for this purpose.

Using my calculator, I found that this area is 0.532. That places 112 in the 53rd percentile.

82 would be in a lower percentile: the 12th percentile.

Let me know if you have questions about how to use a calculator to do these calculations.

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Answer:

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Step-by-step explanation

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Usimov [2.4K]

Answer:

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Step-by-step explanation:

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