Answer:
Step-by-step explanation:
Final concentration % = [grams of salt / mililiters of solution] * 100
grams of salt = grams of salt from solution 1 + grams of salt from solution 2
grams of salt from solution 1 = mililiters * %/100 = 80 mililiters * 0.25 g/mililiters = 20 g
grams of salt from solution 2 = mililiters *%/100 = x*0.10 g/mililiters = 0.1x
mililiters of final solution = mililiters from solution 1 + mililiters from solution 2
mililiters of final solution = 80 mililiters + x mililiters
=> Final concentration, % = [0,10x + 20 g] / [x + 80 mililiters] * 100
The answer is the first one, A
Answer:
Step-by-step explanation:
If we assume that the number of arrivals is normally distributed and we don't know the population standard deviation, we can calculated a 95% confidence interval to estimate the mean value as:
where x' is the population mean value, x is the sample mean value, s is the sample standard deviation, n is the size of the sample, 
is equal to 0.05 (it is calculated as: 1 - 0.95) and 
is the t value with n-1 degrees of freedom that let a probability of 
on the right tail.
So, replacing the mean of the sample by 49, the standard deviation of the sample by 17.38, n by 10 and by 2.2621 we get:
Finally, the interval values that she get is:
Am I opinion the answers either a or B but I’m pretty sure it’s been
