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wlad13 [49]
3 years ago
7

Please help me thanks

Mathematics
2 answers:
rodikova [14]3 years ago
8 0

Answer:

A rational number is a number such as -3/7 that can be expressed as the quotient or fraction a/b of two integers, a numerator q and a non-zero denominator b. Every integer is a rational number: for example, 10 = 10/1.

Advocard [28]3 years ago
7 0

No.

5 \frac{1}{3}

  • First, it is actually a rational number since it can be in a fraction form.
  • Second, it can be turn into a/b where b≠0

So we can turn from 5 1/3 to 16/3

Note that 16/3 makes infinity decimal but if the infinity decimal can be turnt into a fraction, it will be classified as rational number.

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What’s the answer to this problem?
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We can start to solve this problem by using what we know. The recipe calls for 2/3 cup of flour per 1/4 batch of cookies. Now, If we want to write the rate as a complex fraction, we can replace the per with a division sign. This makes it become (2/3)/(1/4) or 
\frac{  \frac{2}{3} }{  \frac{1}{4} } 
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3 years ago
If our school has about 300 seventh graders, about how many would be expect to watch 4 to
kykrilka [37]

Answer:

55

Step-by-step explanation:

7 0
3 years ago
Find a formula for the nth partial sum of the series and use it to find the series' sum if the series converges.
Arisa [49]

Answer: S_n=5(1-\dfrac{1}{n+1}) ; 5

Step-by-step explanation:

Given series : [\dfrac{5}{1\cdot2}]+[\dfrac{5}{2\cdot3}]+[\dfrac{5}{3\cdot4}]+....+[\dfrac{5}{n\cdot(n+1)}]

Sum of series = S_n=\sum^{\infty}_{1}\ [\dfrac{5}{n\cdot(n+1)}]=5[\sum^{\infty}_{1}\dfrac{1}{n\cdot(n+1)}]

Consider \dfrac{1}{n\cdot(n+1)}=\dfrac{n+1-n}{n(n+1)}

=\dfrac{1}{n}-\dfrac{1}{n+1}

⇒ S_n=5\sum^{\infty}_{1}\dfrac{1}{n\cdot(n+1)}=5\sum^{\infty}_{1}[\dfrac{1}{n}-\dfrac{1}{n+1}]

Put values of n= 1,2,3,4,5,.....n

⇒ S_n=5(\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+......-\dfrac{1}{n}+\dfrac{1}{n}-\dfrac{1}{n+1})

All terms get cancel but First and last terms left behind.

⇒ S_n=5(1-\dfrac{1}{n+1})

Formula for the nth partial sum of the series :

S_n=5(1-\dfrac{1}{n+1})

Also, \lim_{n \to \infty} S_n = 5(1-\dfrac{1}{n+1})

=5(1-\dfrac{1}{\infty})\\\\=5(1-0)=5

4 0
3 years ago
A bookcase has 6 shelves.
Bezzdna [24]

Answer:

21 books

Step-by-step explanation:

130-4=x

x/6= answer

6 0
3 years ago
Read 2 more answers
What is 4 3/4 of rupee 1
devlian [24]

Answer:

\frac{19}{4}=Rs 1

Rs. 1 = 100 paise

\frac{19}{4}=100 paise

4.75=100 paise

\frac{4.75}{100}=paise

0.0475=paise

i hope this will help you :)

=1,075

Therefore,

\frac{43}{4} =1,075

Hope it helps you!!!

Plz Mark me as a brailiest

Step-by-step explanation:

5 0
3 years ago
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