Answer:
The proportion of scores reported as 1600 is 0.0032
Step-by-step explanation:
Let X be the score for 1 random person in SAT combining maths and reading. X has distribution approximately N(μ = 1011,σ = 216).
In order to make computations, we standarize X to obtain a random variable W with distribution approximately N(0,1)
The values of the cummulative distribution function of the standard Normal random variable, lets denote it 
are tabulated, you can find those values in the attached file. Now, we are ready to compute the probability of X being bigger than 1600
Hence, the proportion of scores reported as 1600 is 0.0032.
9514 1404 393
Answer:
16
Step-by-step explanation:
48 = 16·3
112 = 16·7
80 = 16·5
3, 5, 7 have no common factors. The GCF of {48, 112, 80} is 16.
_____
It can be helpful to recognize 48 = 16·3 and 80 = 16·5. A simple check shows 112 = 16·7, so 16 is the GCF.
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You can find GCF(48,112) using Euclid's algorithm:
112 mod 48 = 16
48 mod 16 = 0 ⇒ GCF(48, 112) = 16
and the GCF(16, 80) is ...
80 mod 16 = 0 ⇒ GCF(16, 80) = 16
So, GCF(48, 80, 112) is 16.
Answer:
This is a trick that I have learned
Step-by-step explanation:
Just right click on the question or answer
Then click inspect element
and the question will tell you which answer is actually correct
and the answer will tell you if it is correct or not.
Answer:
1728
Step-by-step explanation:
I cant understand the question that well but i think this is the right one
Good evening :)
4 3/4 * 5 3/8
= 19/4 * 43/8
=Multiply numerator together and denominator together
= 817/32
I hope that's help !
