f(x) = (x - 2)^3 + 1
Find the derivative:-
f'(x) = 3(x -2)^2 This = 0 at the turning points:-
so 3(x - 2)^2 =
giving x = 2 . When x = 2 f(x) = 3(2-2)^3 + 1 = 1
Answer is (2, 1)
Answer:
A. 99 sq cm
Step-by-step explanation:
Area of geometric shape
= 2 times the area of one triangle with base a and height c
+ 2 times the area of one triangle with base c and height b
+ Area of rectangle with dimensions a and c.
Sorry this is late but for anyone who still needs it the answer is D. It decreases gross pay by $65.
I just had this on my test, hope it helps :)
The zeros of a quadratic function are found where the graph intersects the x-axis. If the graph interects the x-axis in 2 places, we have 2 real solutions; if the graph intersects--or just touches--the x-axis in one place we have one real solution multiplicity 2; if the graph doesn't go through the x-axis at all we have 2 imaginary solutions. Ours goes through the x-axis in 2 places so we have 2 real solutions. Choice A.
Answer:
black car
Step-by-step explanation:
cbuerif3qopvb vr3yiqtolfhbu;p
