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vaieri [72.5K]
3 years ago
8

What are the factors of the polynomial a^2 + a - 2? Select all that apply.

Mathematics
1 answer:
forsale [732]3 years ago
5 0

Answer:

<h2>A) a - 1 and B) a + 2</h2>

Step-by-step explanation:

a^2+a-2=a^2+2a-a-2=a(a+2)-1(a+2)=(a+2)(a-1)

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PIZZA PARTY 3 medium pizzas for $10.50 how much does it cost to buy 10 medium pizza?
Alja [10]
First you would have to find the cost for 1 medium pizza.

10.50/3=3.5

It costs $3.50 for 1 medium pizza
Next, you would have to multiply 3.5 times 10.

3.5*10=35

It costs $35.00 for 10 medium pizza's.


8 0
3 years ago
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Which equation does the graph of the systems of equations solve?
12345 [234]
Look at the intersecting point on the graph and see the ordered pair then wright it down
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Liz wants to find the quotient of 63 and 0.15. what is the first step she should take?
Veseljchak [2.6K]

Question

Liz wants to find the quotient of 63 and 0.15. what is the first step she should take?

Answer:

→(Well First 63 ÷ 0.15 = 420) ←

A: divide 63 and 0.15 by 10 Would be my Answer

To add two decimal numbers, first check if they have the same number of digits to the right of the decimal point. If they don't, add zeros to the right of one of the numbers until they do. Then, write one number on top of the other, lining up the decimal points vertically.

xXxAnimexXx

5 0
3 years ago
A study is performed in San Antonio to determine whether the average weekly grocery bill per five-person family in the town is s
bogdanovich [222]

Answer:

No, the sample evidence is not statistically significant (P-value = 0.125).

To reject the null hypothesis, the P-value has to be smaller than the significance level, so the significance level to reject the null hypothesis has to be 0.125 or higher.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the average weekly grocery bill per five-person family in San Antonio is significantly different from the national average.

Then, the null and alternative hypothesis are:

H_0: \mu=131\\\\H_a:\mu\neq 131

The significance level is 0.05.

The sample has a size n=50.

The sample mean is M=133.474.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=11.193.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{11.193}{\sqrt{50}}=1.583

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{133.474-131}{1.583}=\dfrac{2.474}{1.583}=1.563

The degrees of freedom for this sample size are:

df=n-1=50-1=49

This test is a two-tailed test, with 49 degrees of freedom and t=1.563, so the P-value for this test is calculated as (using a t-table):

P-value=2\cdot P(t>1.563)=0.125

As the P-value (0.125) is bigger than the significance level (0.05), the effect is  not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the average weekly grocery bill per five-person family in San Antonio is significantly different from the national average.

8 0
3 years ago
Volume of a cone
Monica [59]

Answer:

Answer

Step-by-step explanation:

Answered below :

V

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3 years ago
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