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cluponka [151]
3 years ago
14

ITS TIMED PLEASE HELP​

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
5 0

Answer:

The graph of the function f(x)=\frac{1}{2}x^{2}-4x+5 has a minimum located at (4,-3)

Step-by-step explanation:

we know that

The equation of a vertical parabola in vertex form is equal to

f(x)=a(x-h)^{2}+k

where

a is a coefficient

(h,k) is the vertex of the parabola

If a > 0 the parabola open upward and the vertex is a minimum

If a < 0 the parabola open downward and the vertex is a maximum

In this problem

The coefficient a must be positive, because we need to find a minimum

therefore

Check the option C and the option D

Option C

we have

f(x)=\frac{1}{2}x^{2}-4x+5

Convert to vertex form

f(x)-5=\frac{1}{2}x^{2}-4x

Factor the leading coefficient

f(x)-5=\frac{1}{2}(x^{2}-8x)

f(x)-5+8=\frac{1}{2}(x^{2}-8x+16)

f(x)+3=\frac{1}{2}(x^{2}-8x+16)

f(x)+3=\frac{1}{2}(x-4)^{2}

f(x)=\frac{1}{2}(x-4)^{2}-3

The vertex is the point (4,-3) ( is a minimum)

therefore

The graph of the function f(x)=\frac{1}{2}x^{2}-4x+5 has a minimum located at (4,-3)

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Step-by-step explanation:

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2 years ago
after leaving home for school, it had taken you 15 minutes to walk 1000 feet. if your destination is a total of 1200 feet from h
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Answer: 3 min

Step-by-step explanation:

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Hope this helps!! :)

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4 0
3 years ago
Hey can I have some help with this I am very confused
aniked [119]

#a

m<5=40°

  • Reason-Its Given

#b

m<2=140

  • Reason-Given

#c

<5 and <2 are linear pair(looked properly in diagram) Hence they are supplementary.

#d

<5 and 2 are same side interior angles (Clearly shown on diagram .

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#e

a||b

Let's verify

Let the angle below <1 be <3

Now

<2+<3=180

<5+<4=180

  • <5=<2

\\ \sf\longmapsto

Hence verified

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