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cluponka [151]
4 years ago
14

ITS TIMED PLEASE HELP​

Mathematics
1 answer:
Lubov Fominskaja [6]4 years ago
5 0

Answer:

The graph of the function f(x)=\frac{1}{2}x^{2}-4x+5 has a minimum located at (4,-3)

Step-by-step explanation:

we know that

The equation of a vertical parabola in vertex form is equal to

f(x)=a(x-h)^{2}+k

where

a is a coefficient

(h,k) is the vertex of the parabola

If a > 0 the parabola open upward and the vertex is a minimum

If a < 0 the parabola open downward and the vertex is a maximum

In this problem

The coefficient a must be positive, because we need to find a minimum

therefore

Check the option C and the option D

Option C

we have

f(x)=\frac{1}{2}x^{2}-4x+5

Convert to vertex form

f(x)-5=\frac{1}{2}x^{2}-4x

Factor the leading coefficient

f(x)-5=\frac{1}{2}(x^{2}-8x)

f(x)-5+8=\frac{1}{2}(x^{2}-8x+16)

f(x)+3=\frac{1}{2}(x^{2}-8x+16)

f(x)+3=\frac{1}{2}(x-4)^{2}

f(x)=\frac{1}{2}(x-4)^{2}-3

The vertex is the point (4,-3) ( is a minimum)

therefore

The graph of the function f(x)=\frac{1}{2}x^{2}-4x+5 has a minimum located at (4,-3)

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The manager of a fast food restaurant is supposed to serve coffee that is 160 degrees Fahrenheit. A random sample of 20 cups of
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Answer:

C. No, the Normal/large sample condition is not met.

Step-by-step explanation:

There is only 20 cup and for a sample to meet the Normal/large sample condition it must be greater than 30 samples or have a normal distribution or have no skewness or outliers  

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Find a equation with a slope of -6
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Answer:

y= -6x+2

Step-by-step explanation:

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3 years ago
Read 2 more answers
HELPPPP<br> Which of the following is a solution of x2 + 5x = -2? (2 points)
harkovskaia [24]

Answer:

5.372 or −0.372

Step-by-step explanation:Changes made to your input should not affect the solution:

(1): "x2"   was replaced by   "x^2".

Step by step solution :

STEP

1

:

Trying to factor by splitting the middle term

1.1     Factoring  x2-5x-2

The first term is,  x2  its coefficient is  1 .

The middle term is,  -5x  its coefficient is  -5 .

The last term, "the constant", is  -2

Step-1 : Multiply the coefficient of the first term by the constant   1 • -2 = -2

Step-2 : Find two factors of  -2  whose sum equals the coefficient of the middle term, which is   -5 .

     -2    +    1    =    -1

     -1    +    2    =    1

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Equation at the end of step

1

:

 x2 - 5x - 2  = 0

STEP

2

:

Parabola, Finding the Vertex

2.1      Find the Vertex of   y = x2-5x-2

Parabolas have a highest or a lowest point called the Vertex .   Our parabola opens up and accordingly has a lowest point (AKA absolute minimum) .   We know this even before plotting  "y"  because the coefficient of the first term, 1 , is positive (greater than zero).

Each parabola has a vertical line of symmetry that passes through its vertex. Because of this symmetry, the line of symmetry would, for example, pass through the midpoint of the two  x -intercepts (roots or solutions) of the parabola. That is, if the parabola has indeed two real solutions.

Parabolas can model many real life situations, such as the height above ground, of an object thrown upward, after some period of time. The vertex of the parabola can provide us with information, such as the maximum height that object, thrown upwards, can reach. For this reason we want to be able to find the coordinates of the vertex.

For any parabola,Ax2+Bx+C,the  x -coordinate of the vertex is given by  -B/(2A) . In our case the  x  coordinate is   2.5000  

Plugging into the parabola formula   2.5000  for  x  we can calculate the  y -coordinate :

 y = 1.0 * 2.50 * 2.50 - 5.0 * 2.50 - 2.0

or   y = -8.250

Parabola, Graphing Vertex and X-Intercepts :

Root plot for :  y = x2-5x-2

Axis of Symmetry (dashed)  {x}={ 2.50}

Vertex at  {x,y} = { 2.50,-8.25}

x -Intercepts (Roots) :

Root 1 at  {x,y} = {-0.37, 0.00}

Root 2 at  {x,y} = { 5.37, 0.00}

Solve Quadratic Equation by Completing The Square

2.2     Solving   x2-5x-2 = 0 by Completing The Square .

Add  2  to both side of the equation :

  x2-5x = 2

Now the clever bit: Take the coefficient of  x , which is  5 , divide by two, giving  5/2 , and finally square it giving  25/4

Add  25/4  to both sides of the equation :

 On the right hand side we have :

  2  +  25/4    or,  (2/1)+(25/4)

 The common denominator of the two fractions is  4   Adding  (8/4)+(25/4)  gives  33/4

 So adding to both sides we finally get :

  x2-5x+(25/4) = 33/4

Adding  25/4  has completed the left hand side into a perfect square :

  x2-5x+(25/4)  =

  (x-(5/2)) • (x-(5/2))  =

 (x-(5/2))2

Things which are equal to the same thing are also equal to one another. Since

  x2-5x+(25/4) = 33/4 and

  x2-5x+(25/4) = (x-(5/2))2

then, according to the law of transitivity,

  (x-(5/2))2 = 33/4

We'll refer to this Equation as  Eq. #2.2.1  

The Square Root Principle says that When two things are equal, their square roots are equal.

Note that the square root of

  (x-(5/2))2   is

  (x-(5/2))2/2 =

 (x-(5/2))1 =

  x-(5/2)

Now, applying the Square Root Principle to  Eq. #2.2.1  we get:

  x-(5/2) = √ 33/4

Add  5/2  to both sides to obtain:

  x = 5/2 + √ 33/4

Since a square root has two values, one positive and the other negative

  x2 - 5x - 2 = 0

  has two solutions:

 x = 5/2 + √ 33/4

  or

 x = 5/2 - √ 33/4

Note that  √ 33/4 can be written as

 √ 33  / √ 4   which is √ 33  / 2

Solve Quadratic Equation using the Quadratic Formula

2.3     Solving    x2-5x-2 = 0 by the Quadratic Formula .

According to the Quadratic Formula,  x  , the solution for   Ax2+Bx+C  = 0  , where  A, B  and  C  are numbers, often called coefficients, is given by :

                                   

           - B  ±  √ B2-4AC

 x =   ————————

                     2A

 In our case,  A   =     1

                     B   =    -5

                     C   =   -2

Accordingly,  B2  -  4AC   =

                    25 - (-8) =

                    33

Applying the quadratic formula :

              5 ± √ 33

  x  =    —————

                   2

 √ 33   , rounded to 4 decimal digits, is   5.7446

So now we are looking at:

          x  =  ( 5 ±  5.745 ) / 2

Two real solutions:

x =(5+√33)/2= 5.372

or:

x =(5-√33)/2=-0.372

6 0
3 years ago
Need help on number 15
ollegr [7]
The answer to the question

4 0
3 years ago
Marco calculated that he could run a 5K race in 28 minutes. His actual time was 26 minutes. What is the percent error in his est
sdas [7]

Answer:

7.70%

Step-by-step explanation:

Total length of race = 5k

Actual time taken to run the race = 26 minutes

Marcos time = 28 minutes

Percentage error = difference in value / actual time × 100

= (28 - 26) / 26 × 100

= 2 / 26 × 100

= 0.077 × 100

= 7.70%

7 0
3 years ago
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