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prisoha [69]
2 years ago
6

Help!?!?!?!??!!!!!!!!!!!!!!

Mathematics
2 answers:
Fynjy0 [20]2 years ago
8 0

Answer:

Step-by-step explanation:

Answer d) looks good

Firlakuza [10]2 years ago
6 0

D. \frac{21 \: b}{10}  - 48 ✅

Step-by-step explanation:

- 6( \frac{1}{4}  b+ 10) + 4( \frac{9}{10}b  + 3) \\  =  \frac{ - 6 \: b}{4}  - 60 +  \frac{36 \: b}{10}  + 12 \\  =  \frac{ - 3 \: b}{2}  +  \frac{18 \: b}{5}  - 60 + 12 \\  =   \frac{ - 3 \: b \times 5}{2 \times 5}  +  \frac{18 \: b \times 2}{5 \times 2}  - 48 \\  =  \frac{ - 15 \: b + 36 \: b}{10}  - 48 \\  =  \frac{21 \: b}{10}  - 48

\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘

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50 points For these answers
Y_Kistochka [10]
Answer = 16 square blocks.

There are 16 square blocks in the shape.

I hope this helps.
6 0
3 years ago
Read 2 more answers
Question:
kolbaska11 [484]

Answer:

<u>Proportional relationship formula:</u>

  • y = kx, where k is the constant of proportionality

Use one of the ordered pairs to calculate the value of k

<h3>Company A</h3>

Point (2, 20)

  • 20 = k*2
  • h = 20/2
  • k = 10

The equation: y = 10h

<h3>Company B</h3>

Point (3, 20)

  • 20 = k*3
  • k = 20/3
  • The equation: y = 20/3h

Company A has greater unit rate as 10 > 20/3

3 0
3 years ago
Suppose that $2000 is loaned at a rate of 20%, compounded semiannually. assuming that no payments are made, find the amount owed
skad [1K]
The total amount due after 8 years is 6400
6 0
3 years ago
6. Find the sum of whole number divisible by 3 and lies between 100 and 200.​
MatroZZZ [7]

Answer:

4950

Step-by-step explanation:

first find the smallest multiple of 3 thats >100, 3*33=99, so 3*34=102 is the smallest multiple of 3 >100.

next find the greatest multiple of 3 <200, 3*66=198 which is the greatest multiple of 3<200

34-66+1=number of terms=33. then find the average of the terms: 102+198/2=150. 150*33=4950. the answer should be 4950

3 0
3 years ago
Read 2 more answers
Please explain how to do #3
aleksley [76]
You answered correctly for part a. just simplify it. so for part a it would be x^4 + 8x^3 + 24x^2 + 32x + 16. repeat what you did in part a with part b (add & simplify). btw, the missing side in part c is 2x-x = x
6 0
3 years ago
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