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Sunny_sXe [5.5K]
3 years ago
15

I need help with this. its dividing polynomials

Mathematics
2 answers:
Rasek [7]3 years ago
7 0

Answer:

x^2 + 3x + 9 + 7/x-3

Alex Ar [27]3 years ago
6 0

Answer:

I don't know how to solve it

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What is the area of ABC?
Salsk061 [2.6K]

Answer:

Area of triangle ABC = 10

Option C is correct.

Step-by-step explanation:

We need to find area of triangle ABC

We are given A(2,1) B(4,7) and C(6,3)

The formula used to find Area \ of \ triangle=\frac{1}{2}base\times height ABC is:

In the given triangle base= AC and height = BC

First we need to find the distance between A and C and B and C

The formula used to find distance between AC Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We have x_1=2, y_1=1, x_2=6, y_2=3

Putting values and finding distance

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\Distance=\sqrt{(6-2)^2+(3-1)^2}\\Distance=\sqrt{(4)^2+(2)^2}\\Distance=\sqrt{16+4}\\Distance=\sqrt{20}

find distance between BC Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We have x_1=4, y_1=7, x_2=6, y_2=3

Putting values and finding distance

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\Distance=\sqrt{(6-4)^2+(3-7)^2}\\Distance=\sqrt{(2)^2+(4)^2}\\Distance=\sqrt{4+16}\\Distance=\sqrt{20}

So, We have height = \sqrt{20} and base = \sqrt{20}

Finding area of triangle

Area \ of \ triangle=\frac{1}{2}base\times height\\Area \ of \ triangle=\frac{1}{2}\sqrt{20} \times \sqrt{20} \\Area \ of \ triangle=\frac{1}{2}\times 20\\Area \ of \ triangle=10

So, Area of triangle ABC = 10

Option C is correct.

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