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2 years ago

Help! Need sober answer....

Mathematics

1 answer:

AlekseyPX2 years ago

6 0

$\huge{\mathbb{\tt{ANSWER↓}}}$

<h3><u>1. Find the permutation of the word LOVE taken 2 letters at a time.</u></h3>

<h2><u>ANSWER</u><u> </u><u>IS</u><u> </u><u>C.12</u></h2>

<h3><u>2. If 3 girls enter a jeepney in which there are 7 vacant seats, how many ways are there for them to be seated?</u></h3>

<h2><u>ANSWER</u><u> </u><u>IS</u><u> </u><u>B.210</u></h2>

<h3><u>3. How many combinations can be made from the letters of the word MOTHER taken 4 at a time.</u></h3>

<h2><u>ANSWER</u><u> </u><u>IS</u><u> </u><u>A.15</u></h2>

#CarryOnLearning

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<h3>→XxKim02xX</h3>

You might be interested in

-1/6 + 2/3 ( 9 + - 3/4) + - 1/2

Liono4ka [1.6K]

First simplify the section in the parenthesis.
-1/6 + 2/3(8 1/4) + -1/2
Then multiply 2/3 by 8 1/4.
-1/6 + 5 1/2 + -1/2
Add -1/2 to 5 1/2.
-1/6 + 5
Add 5 to -1/6.
4 5/6 is the fully simplified answer.
Hope this helps!

7 0

2 years ago

A sum of two mixed numbers is given.<br><br> What is the missing number?

kaheart [24]

Answer:

16.

Step-by-step explanation:

The whole numbers stay the same so it stays as 2. The way they get 30 for the denominator is by multiplying the fraction 1/3 by 10 and 1/5 by 6. So now we have 10/30 and 6/30. Add them together, 10+6=16

4 0

2 years ago

Which of the following equations is true?

Korolek [52]

Answer:

Step-by-step explanation:

10×1=10

0+10=10

Hence they're equal

7 0

2 years ago

Q.6. The equation of the ellipse whose centre is at the origin and the x-axis, the major axis, which passes

azamat

<h3>Answer:</h3>

Equation of the ellipse = 3x² + 5y² = 32

<h3>Step-by-step explanation:</h3>

<h2>Given:</h2>

The centre of the ellipse is at the origin and the X axis is the major axis

It passes through the points (-3, 1) and (2, -2)

The equation of the ellipse

<h2>Solution:</h2>

The equation of an ellipse is given by,

$\sf \dfrac{x^2}{a^2} +\dfrac{y^2}{b^2} =1$

Given that the ellipse passes through the point (-3, 1)

Hence,

$\sf \dfrac{(-3)^2}{a^2} +\dfrac{1^2}{b^2} =1$

Cross multiplying we get,

9b² + a² = 1 ²× a²b²
a²b² = 9b² + a²

Multiply by 4 on both sides,

4a²b² = 36b² + 4a²------(1)

Also by given the ellipse passes through the point (2, -2)

Substituting this,

$\sf \dfrac{2^2}{a^2} +\dfrac{(-2)^2}{b^2} =1$

Cross multiply,

4b² + 4a² = 1 × a²b²
a²b² = 4b² + 4a²-------(2)

Subtracting equations 2 and 1,

3a²b² = 32b²
3a² = 32
a² = 32/3----(3)

Substituting in 2,

32/3 × b² = 4b² + 4 × 32/3
32/3 b² = 4b² + 128/3
32/3 b² = (12b² + 128)/3
32b² = 12b² + 128
20b² = 128
b² = 128/20 = 32/5

Substituting the values in the equation for ellipse,

$\sf \dfrac{x^2}{32/3} +\dfrac{y^2}{32/5} =1$

$\sf \dfrac{3x^2}{32} +\dfrac{5y^2}{32} =1$

Multiplying whole equation by 32 we get,

3x² + 5y² = 32

<h3>Hence equation of the ellipse is 3x² + 5y² = 32</h3>

8 0

2 years ago

A city's mean minimum daily temperature in February is 28°F. Suppose the standard deviation of the minimum temperature in Febru

DIA [1.3K]

Answer:

i think you might have to round or something

Step-by-step explanation:

6 0

3 years ago

Help! Need sober answer....​

Help! Need sober answer....