7y! they are like terms :p
A quadratic equation is of the format:
ax² + bx + c = 0, where a ≠ 0.
The first option is not quadratic, it is a cubic, it has highest power of 3.
The second option f (x) = 3/4 x ^2 + 2x − 5, is quadratic, that is the answer.
The third f(x) = 4/x^2 - 2/x + 1, doesn't qualify because of the 2/x.
The last f(x) = 0x^2 − 9x + 7
, doesn't qualify because of the a = 0, and the rule is that a ≠ 0.
Therefore f (x) = 3/4 x ^2 + 2x − 5 represents a quadratic function.
I hope this helps.
9514 1404 393
Answer:
9°, 9°, 162°
Step-by-step explanation:
Let x represent the measure of the first angle. Then the sum of all of the angles in the triangle is ...
x + x + 9(x+x) = 180°
20x = 180° . . . . . . . . . . collect terms
x = 180°/20 = 9° . . . . . divide by 20
9(x+x) = 162° . . . . . . . find the third angle
The three angle measures are 9°, 9°, and 162°.
Answer:
3 units
Step-by-step explanation:
∠A = ∠E (same arc BD)
∠X share
ΔXDA similar to ΔXBE
XE / XA = XB / XD
(3 + DE) / 9 = 2 / 3
9 + 3DE = 18
3DE = 9
DE = 3
