Answer:
1) Total outcomes of 1 time = 16
2) 36 times
3) 24 times
Step-by-step explanation:
<h3>1) Total outcomes</h3>
If both spinners are spinning together, and are labelled from 1 to 4, the the outcome are:
{(1, 1), (1, 2), (1, 3), (1, 4), (2, 1), (2, 2), (2, 3), (2, 4), (3, 1), (3, 2), (3, 3), (3, 4), (4, 1), (4, 2), (4, 3), (4, 4)}
We can count them to find total no. of outcomes
Total outcomes = 16
<h3>
2) When Difference = 1</h3>
Following combinations have a difference of 1
{(1, 2), (2, 1), (2, 3), (3, 2), (3, 4), (4, 3)}
n = 6
Probability of getting such combination is: 6/16
How many times Harvey would get such a combination out of 96 times?
<h3>
3) When Difference = 0</h3>
Following combinations have a difference of 0
{(1, 1), (2, 2), (3, 3), (4, 4)}
n=4
Probability of getting such combination is: 4/16
How many times Harvey would get such a combination out of 96 times?