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Komok [63]
3 years ago
5

Plz help me i suck at this ;-;

Mathematics
2 answers:
larisa [96]3 years ago
8 0

Answer:

The correct answer is: Isosceles.

Step-by-step explanation:

First let’s take a look at ‘Right’. Right, is determining the angle, not the side length.

’Obtuse’. Obtuse is also determinin the angle, therefore it cannot be the correct answer.

’Parallel’. It is impossible for a triangle to be parallel, meaning that there are two opposite sides, incapable of touching each other.

’Isosceles‘ for a triangle to be isosceles, it needs two sides made of equal length. This description connects with the question being asked, therefore ‘Isosceles‘ is the correct answer.

insens350 [35]3 years ago
4 0

Answer:

The answer is obtuse

Step-by-step explanation:

because a triangle cannot be a right or parallel or a Isosceles.

Hope this helps!:)

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lakkis [162]
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3 years ago
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Rashid [163]

Answer:

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Step-by-step explanation:

7 0
3 years ago
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By [n][n] we denote the set {1,…,n}. A function f:[m]→[n] is called monotone if f(i) \leq f(j)f(i)≤f(j)whenever i < ji
Dafna11 [192]

Answer:

There are a total of  { 6 \choose 3} = 20 functions.

Step-by-step explanation:

In order to define an injective monotone function from [3] to [6] we need to select 3 different values fromm {1,2,3,4,5,6} and assign the smallest one of them to 1, asign the intermediate value to 2 and the largest value to 3. That way the function is monotone and it satisfies what the problem asks.

The total way of selecting injective monotone functions is, therefore, the total amount of ways to pick 3 elements from a set of 6. That number is the combinatorial number of 6 with 3, in other words

{6 \choose 3} = \frac{6!}{3!(6-3)!} = \frac{720}{6*6} = \frac{720}{36} = 20  

3 0
3 years ago
which expression have a value of 16/81? check all that apply. (2/3)^4, (16/3)^4, (4/81)^2, and (4/9)^2
notka56 [123]

Use\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\\left(\dfrac{2}{3}\right)^4=\dfrac{2^4}{3^4}=\dfrac{16}{81}\ :)\\\\\left(\dfrac{16}{3}\right)^4=\dfrac{16^4}{3^4}=\dfrac{16^4}{81}\neq\dfrac{16}{81}\ :(\\\\\left(\dfrac{4}{81}\right)^2=\dfrac{4^2}{81^2}=\dfrac{16}{81^2}\neq\dfrac{16}{81}\ :(\\\\\left(\dfrac{4}{9}\right)^2=\dfrac{4^2}{9^2}=\dfrac{16}{81}\ :)

6 0
3 years ago
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2/4 is more than 1/4?
Mazyrski [523]

Answer:

Yes!

Step-by-step explanation:

Yes, because 2>1.

4 0
3 years ago
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