Which of these relations are functions? Select all that apply

Electronic bulletin boards, combining the

snow_lady [41]

(D) "subjects as diverse as"

"As...as" is the proper construct to employ when comparing items that are equal in some sense, therefore using "as" in this context is inappropriate (which is what happens in the sentence) So, the correct response is D.

Choice (A) uses awkward wording. As demands "such" come before it. Option (B) uses awkward wording. Should read "such as," not "that are." An incorrect idiom is present in Option (C).

It should be "diversity such as," not "such diversity." There is an agreement issue with Option (E) (in number). The various subjects mentioned cannot be referred to as "a subject".

Here's a question with an answer similar to this about improper phrasing: brainly.com/question/15806900

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7 0

2 years ago

A jumbo crayon is composed of a cylinder with a conical tip. The cylinder is 12 cm tall with a radius of 1.5 cm, and the cone ha

s2008m [1.1K]

Answer:

Part 1) The lateral area of the cone is $LA=2\pi\ cm^{2}$

Part 2) The lateral surface area of the cylinder is $LA=36\pi\ cm^{2}$

Part 3) The surface area of the crayon is $SA=41.50\pi\ cm^{2}$

Step-by-step explanation:

Part 1) Find the lateral area of the cone

The lateral area of the cone is equal to

$LA=\pi rl$

we have

$r=1\ cm$

$l=2\ cm$

substitute

$LA=\pi (1)(2)$

$LA=2\pi\ cm^{2}$

Part 2) Find the lateral surface area of the cylinder

The lateral area of the cylinder is equal to

$LA=2\pi rh$

we have

$r=1.5\ cm$

$h=12\ cm$

substitute

$LA=2\pi (1.5)(12)$

$LA=36\pi\ cm^{2}$

Part 3) Find the surface area of the crayon

The surface area of the crayon is equal to the lateral area of the cone, plus the lateral area of the cylinder, plus the top area of the cylinder plus the bottom base of the crayon

Find the area of the bottom base of the crayon

$A=\pi[r2^{2}-r1^{2}]$

where

r2 is the radius of the cylinder

r1 is the radius of the cone

substitute

$A=\pi[1.5^{2}-1^{2}]$

$A=1.25\pi\ cm^{2}$

Find the area of the top base of the cylinder

$A=\pi(1.5)^{2}=2.25\pi\ cm^{2}$

Find the surface area

$SA=2\pi+36\pi+2.25\pi+1.25\pi=41.50\pi\ cm^{2}$

8 0

3 years ago

Read 2 more answers

In this situation, which equation is NOT equivalent to the rest? Mrs. Jones deducts $3 from each of her 5 children's allowances

lawyer [7]

Answer:

c. 5x - 3 = 125

Step-by-step explanation:

Mrs. Jones deducts $3 from each of her 5 children's allowances this week because they didn't finish their chores. They then received a total of $125 in allowance. a. 5(x - 3) = 125

b. 5x - 15 = 125

c. 5x - 3 = 125

d. 5x = 140

Solution:

Let x represent the allowance for each of Mrs. Jones children. Since she deducts $3 from each children because they didn't finish their chores, the allowance for each child becomes x - 3.

There are 5 children, hence the allowance for the 5 children would be:

5(x-3)

Since they received a total of $125 in allowance, hence:

5(x-3) = 125

5x - 15 = 125

5x = 125 + 15

5x = 140

Option c is wrong

3 0

3 years ago

If you flip a coin and roll a 6-sided die, what is the probability that you will flip a heads and roll at least a 3?

levacccp [35]

Probability of coin flip = 1/2, probability of die roll = 4/6
1/2 * 4/6 = 1/3 chance

7 0

4 years ago

What is the range for the possible ratios of adjacent leg hypotenuse ratios?

kaheart [24]

Answer:

3 triangles have adjacent leg to hypotenuse ratios of approximately 0.91.

Step-by-step explanation:

3 0

2 years ago

Which of these relations are functions? Select all that apply​

Which of these relations are functions? Select all that apply