Answer:
22 + x = 43
Step-by-step explanation:
let x = vanessa's savings
22 + x = 43
Answer:

Step-by-step explanation:
Given

<em>See attachment for options.</em>
Required
Determine which of the options answers the question
Analyzing the option one after the other:

Multiply through by y


Divide through by 4


This can be rewritten as


By comparison with 
we have:



<em>Hence: this answers the question.</em>
a) The students who are members of both sets can be described by
... a ∩ b
b) The students who are members of a but not b can be described by
... a ∩ b'
c) The students who are members of one or both sets can be described by
... a ∪ b
d) The students who are not in one set or not in the other set can be described by
... a' ∪ b' . . . . = (a ∩ b)'
Answer:
If you mean only one rational solution, the answer is

If you mean at least 1 rational solution, the answer is
![k\in (-\infty, -8]\cup[8, \infty)](https://tex.z-dn.net/?f=k%5Cin%20%28-%5Cinfty%2C%20-8%5D%5Ccup%5B8%2C%20%5Cinfty%29)
Step-by-step explanation:

Let's calculate the discriminant.



Now, remember that:



Therefore, I will just consider the first two cases.

and




