Question has missing details (Full question below)
Measurement error that is continuous and uniformly distributed from –3 to +3 millivolts is added to a circuit’s true voltage. Then the measurement is rounded to the nearest millivolt so that it becomes discrete. Suppose that the true voltage is 219 millivolts. What is the mean and variance of the measured voltage
Answer:
Mean = 219
Variance = 4
Step-by-step explanation:
Given
Let X be a random variable measurement error.
X has a discrete uniform distribution as follows
a = 219 - 3 = 216
b = 219 + 3 = 222
Mean or Expected value is calculated as follows;
E(x) = ½(216+222)
E(x) = ½ * 438
E(x) = 219
Variance is calculated as follows;
Var(x) = ((b-a+1)²-1)/12
Var(x) = ((222-216+1)²-1)/12
Var(x) = (7²-1)/12
Var(x) = 48/12
Var(x) = 4
Answer: 2/1
Step-by-step explanation:
2/1 because you use rise/run which is moving up 2 units from (0,3) to (0,5) and then moving right 1 unit to (1,5)
Answer:
Step-by-step explanation:
given that the U.S. Department of Housing and Urban Development (HUD) uses the median to report the average price of a home in the United States.
We know that mean, median and mode are measures of central tendency.
Mean is the average of all the prices while median is the middle entry when arranged in ascending order.
Mean has the disadvantage of showing undue figure if extreme entries are there. i.e. outlier affect mean.
Suppose a price goes extremely high, then mean will fluctuate more than median.
So median using gives a reliable estimate since median gives the middle price and equally spread to other sides.
C=10, C=90°, B=30°, A+B+C=180°
A+30°+90°=180°⇒A=60°
cos30°=a/c
cos30°=a/10⇒a=cos30°*10
a<span>≃8.6602
c²=a²+b²⇒b²=c²-a²
b²=10²-8.6602²⇒b²=25
b=5
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I am pretty sure the answer would be -.02
Bc you would do 2-3.6/5- -3
