Answer:
The sampling distribution of
is:
.
Step-by-step explanation:
According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.
The mean of this sampling distribution of sample proportion is:
The standard deviation of this sampling distribution of sample proportion is:
![\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}](https://tex.z-dn.net/?f=%5Csigma_%7B%5Chat%20p%7D%3D%5Csqrt%7B%5Cfrac%7Bp%281-p%29%7D%7Bn%7D%7D)
The study was conducted using the data from 15,000 students.
Since the sample size is so large, i.e. <em>n</em> = 15000 > 30, the central limit theorem is applicable to approximate the sampling distribution of sample proportions.
So, the sampling distribution of
is:
.
Answer:
Days can Stefan feed
Coco with the oats he has left is 5 days
Step-by-step explanation:
Total Oats = 4 1/2 cups
He uses 3 1/4 cups to make granola bars for
a camping trip
Remaining oats after making granola bars = Total oats - oats used for granola bars
= 4 1/2 - 3 1/4
.= 9/2 - 13/4
= 18-13/4
= 5/4 cups
Remaining oats after making granola bars is 5/4 cups
Coco needs 1/4 of a cup of oats each day, how many days can Stefan feed
Coco with the oats he has left?
Days can Stefan feed
Coco with the oats he has left = Remaining oats / 1/4 cups
= 5/4 cups ÷ 1/4 cups
= 5/4 × 4/1
= 20/4
= 5 days
Days can Stefan feed
Coco with the oats he has left is 5 days
Just like you round to the rearst whole number 4 and below gose down 5 and up gose up
Answer:
4
Step-by-step explanation:
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