Answer:
![\$532,166.99 \text{ (to the nearest penny)}](https://tex.z-dn.net/?f=%5C%24532%2C166.99%20%5Ctext%7B%20%20%28to%20the%20nearest%20penny%29%7D)
Step-by-step explanation:
![Amount \: at \: Compound \: Interest= P(1+\frac{r}{k} )^{nk}](https://tex.z-dn.net/?f=Amount%20%5C%3A%20at%20%5C%3A%20Compound%20%5C%3A%20Interest%3D%20P%281%2B%5Cfrac%7Br%7D%7Bk%7D%20%29%5E%7Bnk%7D)
Principal, P=$10
Rate,r =5%
Compounding Period,K=4 (Quarterly)
Number of Years, n=2019-1800=219 Years
![\text{Balance as at April 30th 2019}= 10(1+\frac{0.05}{4} )^{219*4}\\=10(1+0.0125 )^{876}\\=10(1.0125 )^{876}\\\approx\$532166.99 \text{ (to the nearest penny)}](https://tex.z-dn.net/?f=%5Ctext%7BBalance%20as%20at%20April%2030th%202019%7D%3D%2010%281%2B%5Cfrac%7B0.05%7D%7B4%7D%20%29%5E%7B219%2A4%7D%5C%5C%3D10%281%2B0.0125%20%29%5E%7B876%7D%5C%5C%3D10%281.0125%20%29%5E%7B876%7D%5C%5C%5Capprox%5C%24532166.99%20%5Ctext%7B%20%20%28to%20the%20nearest%20penny%29%7D)
Assuming that 10% is the probability of a switch being defective (since left-handedness has nothing to do with the problem):
For a binomial distribution, probability(r out of n) = (nCr) (p)^r (q)^(1-r)
p = 10% = 0.1, q = 1 - p = 0.9
r = 2 switches, n = total of 12 switches
probability = (12C2) (0.1)^2 (0.9)^(12-2)
probability = 66(0.1)^2 (0.9)^10
probability = 0.23
This problem equals up to 19.6666667 for
multiplying
So to find the answer you want to isolate the y. So the first thing you want to do is to move everything to the opposite side of the = sign. You start by adding 10 to both sides.
10+ 5y -10 = -25 +10
5y = -15.
the tens cancel out on the left side and on the right you get left with -15/
Since y is being multiplied by 5 you always want to do the opposite so you divide by 5.
5y/5 = -15/5
y = -3
It's hard to explain but you just have to remember that what you do to one side you must do to the other to keep the equation balanced.
Answer:
y = 1/3x – -2
Step-by-step explanation:
When x=0, y = -2
When y=0, x = 6