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natta225 [31]
2 years ago
15

1. In the expression x2, 2 is what we callA. BaseB. ExponentC. Multiple ​

Mathematics
2 answers:
gtnhenbr [62]2 years ago
8 0
2 would be the exponent. X would be the base.
11111nata11111 [884]2 years ago
6 0

Answer:

hello! if you're talking about x², then 2 is what we call: B. Exponent.

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X divided by 2=86

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If (x^2 - 1) is a factor of ax^4 + bx^3 + cx^2 + dx + e, show that a + c + e = b + d = 0
alisha [4.7K]
x^2-1=x^2-1^2=(x-1)(x+1)

If x²-1 is a factor of the polynomial, both x-1 and x+1 are factors of it.

According to the remainder theorem, if a binomial x-a is a factor of a polynomial p(x), then p(a)=0.

If x-1 and x+1 are factors of the polynomial p(x)=ax⁴+bx³+cx²+dx+e, then p(1)=0 and p(-1)=0.

p(1)=a \times 1^4+b \times 1^3 + c \times 1^2+ d \times 1+e \\
p(-1)=a \times (-1)^4 + b \times (-1)^3 + c \times (-1)^2 + d \times (-1)+e \\ \\
p(1)=a+b+c+d+e \\
p(-1)=a-b+c-d+e \\ \\
p(1)=0 \\
p(-1)=0 \\ \\ \hbox{add both equations:} \\
a+b+c+d+e=0 \\
\underline{a-b+c-d+e=0} \\
2a+2c+2e=0 \\
2(a+c+e)=0 \\
a+c+e=0 \\ \\
\hbox{substitute 0 for a+c+e in the first equation:} \\
a+b+c+d+e=0 \\
(a+c+e)+b+d=0 \\
0+b+d=0 \\
b+d=0 \\ \\
\boxed{a+c+e=b+d=0} \\
\hbox{proved } \checkmark
8 0
3 years ago
Question 1 of 10
AleksAgata [21]

Answer:

True

Step-by-step explanation:

3 0
2 years ago
Which set of numbers is correctly ordered from least to greatest? <img src="https://tex.z-dn.net/?f=A.%29%20%5Cfrac%7B24%5Cpi%20
labwork [276]

Answer:

A

Step-by-step explanation:

24pie/5 is 15.07

63/4 is 15.75

15.758

956 square root e is 1576.17

Therefor, the order would be A

5 0
3 years ago
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