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nlexa [21]
3 years ago
10

In a group of 90 seventh

Mathematics
2 answers:
Firdavs [7]3 years ago
5 0
90 x .80= 72. 72 Students like hot choco, therefore 8 do no like hot choco
Inessa05 [86]3 years ago
3 0

Answer: 18

Step-by-step explanation:

90 / 10 = 9 (10%)

9 x 8 = 72 (80%)

90 - 72 = 18 (20%)

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Pls help me with this answer choice question! brainliest, rattings, thanks etc.
galina1969 [7]

Answer:

graph B

Step-by-step explanation:

Given

3y - 5x < - 6

Since the inequality is < then the line must be broken

If ≤ then line would be solid

The only possible graphs are B and D

Choose a test point in the shaded region of each graph and check validity

graph B (2, 0) ← substitute into left side of inequality

0 - 5(2) = 0 - 10 = - 10 < - 6 ← this is valid

graph D (0, 0 ) ← substitute into left side of inequality

0 - 0 = 0 > - 6 ← this is not valid

Hence graph B is the correct graph

3 0
3 years ago
Solve 0.05p-0.02(5-2p)=0.05(p-2)-0.12
Montano1993 [528]
0.05p-0.02(5-2p)=0.05(p-2)-0.12 

0.05p-0.02(5-2p)=0.05(p-2)-0.12:p 

&#10;0.05p-0.1+0.04p=0.05p-0.1-0.12&#10; &#10;  |Expand \ the \ equation| 

0.09p-0.1=0.05p-0.1-0.12&#10; &#10; 

0.09p-0.1=0.05p-0.22 

&#10;0.09p-0.1-0.05p=-0.22&#10; &#10;&#10;  |Subtract \ 0.05p \ from \ both \ sides| 

&#10;0.04p-0.1=-0.22&#10; &#10; 

&#10;0.04p=-0.22+0.1&#10; &#10;  |Add \ 0.1 \ to \ both \ sides| 

&#10;0.04p=-0.12&#10; &#10; 

0.04p/0.04=-0.12/0.04&#10;  |Divide \ both \ sides \ by \ 0.04| 

p=-3 

\star \ Hence \ Solved
8 0
3 years ago
20y^2-34y+6 (factoring)
denpristay [2]
Hello There!

Your answer is 2(5y - 1)(2y - 3)

Hope This Helps You!
Good Luck :) 

- Hannah ❤
3 0
3 years ago
Your grandfather gave you $1.65 with
Lelu [443]

Answer:

$1.98

Step-by-step explanation:

1.65/5=0.33

1.65+0.33=1.98

check: 1.98/6 =0.33

0.33x5=1.65

5 0
3 years ago
Read 2 more answers
A particular paper included the accompanying data on the tar level of cigarettes smoked for a sample of male smokers who subsequ
Dafna1 [17]

Answer:

Check the explanation

Step-by-step explanation:

H_0:proportion of male smoker lung deaths is same for the four given tar level categories.

H_1:proportion of male smoker lung deaths is not the same for the four given tar level categories.

Expected frequency=1177/4=294.25

Tar level     Observed Freq.(O)        Expected Freq.(E)         (O-E)^2/E

0-7                         107                                   294.25                120.435

8-14                        375                                  294.25                5.643

15-21                       553                                 294.25                 227.533

>=22                       183                                  294.25                 42.061

Total=                    1177                                  1177                      395.673

Total chi square score=395.673

df=4-1=3

p-value=CHIDIST(395.673,3)<0.001

p-value<0.001,Reject null hypothesis.

There is sufficient evidence that the proportion of male smoker lung deaths is not the same for the four given tar level categories.

5 0
3 years ago
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