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Triss [41]
3 years ago
7

If a=i+7j+k and b=i+11j+k, find a unit vector with positive first coordinate orthogonal to both a and

Mathematics
1 answer:
Scilla [17]3 years ago
5 0
Take the cross product, then normalize the result.

\mathbf a\times\mathbf b=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\1&7&1\\1&11&1\end{vmatrix}=-4\,\mathbf i+4\,\mathbf k

This has norm

\|\mathbf a\times\mathbf b\|=\sqrt{(-4)^2+4^2}=4\sqrt2

and so a unit vector orthogonal to both given vectors is

\dfrac{\mathbf a\times\mathbf b}{\|\mathbf a\times\mathbf b\|}=-\dfrac1{\sqrt2}\,\mathbf i+\dfrac1{\sqrt2}\,\mathbf k

An equally correct answer would be the negative of this vector, since \mathbf b\times\mathbf a=-\mathbf a\times\mathbf b.
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Find the measurement of angle 2
N76 [4]

Answer:

∠ 2 = 25°

Step-by-step explanation:

The triangle on the right has 2 congruent sides and is therefore isosceles with 2 base angles being congruent, both 65° , then

∠ 2 = \frac{180-(65+65)}{2} = \frac{180-130}{2} = \frac{50}{2} = 25°

4 0
3 years ago
Easy Question pls help. (Algebra II type problems)
Roman55 [17]

Answer:

\large\boxed{if\ x\neq-3\ \wedge\ y\neq0\ \wedge\ x\neq y\ \wedge\ x\neq -y}

second

\large\boxed{y\neq0\ \wedge\ x\neq-y\ (y\neq-x)}

Step-by-step explanation:

We know that dividing by 0 is impossible.

Therefore, the denominator of the expression must be different from 0.

\text{For}\\\\\dfrac{(x-y)^2}{2xy+6y}\times\dfrac{4x+12}{x^2-y^2}\\\\\\2xy+6y\neq0\qquad(1)\\\\x^2-y^2\neq0\qquad(2)

(1)\\2xy+6y\neq0\qquad\text{distribute}\\\\2y(x+3)\neq0\iff2y\neq0\ \wedge\ x+3\neq0\\\\2y\neq0\qquad\text{divide both sides by 2}\\\boxed{y\neq0}\\\\x+3\neq0\qquad\text{subtract 3 from both sides}\\\boxed{x\neq-3}\\==========================\\(2)\\x^2-y^2\neq0\qquad\text{use}\ a^2-b^2=(a-b)(a+b)\\(x-y)(x+y)\neq0\iff x-y\neq0\ \wedge\ x+y\neq0\\\boxed{x\neq y}\ \wedge\ \boxed{x\neq-y}

\text{For}\\\\\dfrac{2(x-y)}{y(x+y)}\\\\y(x+y)\neq0\iff y\neq0 \wedge\ x+y\neq0\\\\ \boxed{y\neq0}\ \wedge\ \boxed{x\neq-y}

3 0
3 years ago
A SQUARE PATIO HAS AN AREA OF 200 SQUARE FEET. HOW LONG IS EACH SIDE OF THE PATIO TO THE NEAREST 0.05
lara [203]
If you would like to know the length of each side of the patio, you can calculate this using the following steps:

an area ... 200 square feet
a ... the length of one side

area = a * a = a^2
200 = a^2
a = sqrt(200)
a = 14.14 feet

The correct result would be 14.14 feet.
6 0
3 years ago
Solve and check: ½ (c – 24) + 2/3c = 9
Taya2010 [7]
The answer is see you happy new year
4 0
3 years ago
What is the range?<br> 2 4 4 5 4
xxMikexx [17]

Answer:

3 :)

Step-by-step explanation:

7 0
3 years ago
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