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jeka94
2 years ago
8

A parabola opening up or down has vertex (0, -2) and passes through (8, -18). Write its

Mathematics
1 answer:
madreJ [45]2 years ago
5 0

Answer:

<u>f(x) = -1/4(x - 0)^2 - 2</u>

Step-by-step explanation:

vertex form:

f(x) = a(x - h)^2 + k

<em>1) put the vertex in the equation, ( (h, k) is the vertex)</em>

f(x) = a(x - 0)^2 - 2

<em>2) plug in the point (8, -18) to find the value of a</em>

-18 = a(8 - 0)^2 - 2

-18 = a(64) - 2

-16 = a(64)

-16/64 = a

-1/4 = a

<em>3) plug in the value of a into the equation</em>

<u>f(x) = -1/4(x - 0)^2 - 2</u>

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Can someone please help me solve this?
aleksklad [387]

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