Question

GIVEN: ab perpendicular to BC AND DC PERPENDICULAR TO BCAC = BDPROVE:AB =DC Proofs

Answer 1

Answer with Step-by-step explanation:

We are given that AB is perpendicular to BC and DC perpendicular to BC.

AC=BD

We have to prove that AB=DC

In triangle ABC and triangle DCB

AC=BD  (Given)

$\angle B=\angle C=90^{\circ}$

$BC=BC$

Reason:Reflexive property

$\triangle ABC\cong \triangle DCB$

Reason:RHL postulate

$AB\cong DC$

Reason:CPCT

Therefore, AB=DC when two sides are congruent then the sides are equal.

Hence, proved.

Answer 2

Let's take a look at the triangles ABC and DCB

1. angles : B=C=90° because they are right triangles (AB perpendicular to BC and DC perpendicular to BC)

2. AC=BD (given)
3. BC is in common (the two triangles have it, you can say it like BC=BC)

So we proved that by SAS(side angle side), the triangles are congruent ABC= DCB

Since the triangles are congrueny, all their sides are equal so we can say that AB=DC