F(59)=3x-2
f(59)=3(59)-2
f(59)=177-2
f(59)=175
For the experiment, you need 2L of cola. Your first option would be to purchase 1 2L bottle of cola for $2.25.
To calculate the second option, let's convert milliliters to liters first. There are 1,000 milliliters in 1 liter. With this, we know that there are 2,000 milliliters in 2 liters. Option 2 comes in 500-milliliter cans, which means that you would need 4 of them (2,000/500 = 4). 4 cans multiplied by $0.50 would cost you $2.00.
Let's check the cost of your answer options.
A. 4 cans - As seen above, this would cost $2.00.
B. 1 bottle - From the question, we know this would cost $2.25.
C. 2 bottles - This would be more soda than you need and would cost $4.50 ($2.25x2)
D. 1 can - This would be .5L and not enough soda for the experiment.
E. 5 cans - This would cost $2.50, but would be an extra 500mL of soda.
F. 2 cans - This would only be 1L of soda and not enough for the experiment.
G. 3 cans - This would be 1.5L of soda and not enough for the experiment either.
For the best price option, you would choose A (four cans of soda). This would give you the amount of soda that you need at the lowest price.
Answer:
5%
Step-by-step explanation:
Amount of money that is discounted
= $15 - $14.25
$0.75
Percentage that needed to be discount
=(0.75/15) * 100%
= 5%
Thus, owner needs to discount 5% to discount his pizza from $15 to $14.25.
To be able to compare the rates, we will write them in fraction form.
The fraction that represents Joe's rate is:

and the fraction that represents Bob's rate is:

Simplifying the above fractions, we get:

Since:

then Bob and Joe did not work at the same rate.
Answer:
No, Bob and Joe did not work at the same rate.
9514 1404 393
Answer:
- |w -30| > 1.6
- (-∞, 28.4) U (31.6, ∞)
Step-by-step explanation:
1. The snack bags will be rejected if their weight differs from 30 grams by more than 1.6 grams:
|w -30| > 1.6
__
2. This inequality resolves to two inequalities.
w -30 > 1.6
w > 31.6 . . . . . add 30
and
-(w -30) > 1.6
w -30 < -1.6 . . . multiply by -1
w < 28.4 . . . . . add 30
The solution in interval notation is the union of the two disjoint intervals:
(-∞, 28.4) U (31.6, ∞)