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3 years ago

Out of the 40 students in the 7th grade 60% of the students carry cell phones. What fraction of the students carry a cell phone?

Mathematics

2 answers:

Volgvan3 years ago

7 0

The answer is 24 students. The fraction is 24/40. The fraction in simplest form is 3/5.

nexus9112 [7]3 years ago

6 0

If you have 60% out of 40 students that is 24 students

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Answer the question and prove your answer on a separate piece of paper. 1 point

EastWind [94]

Answer:

as below

Step-by-step explanation:

it's negative 4 or -4 is the rate of change or aka the slope

show the teacher the graph, which is free and also online. ( Demos )

:) you can make that graph also is my point

6 0

2 years ago

A gym charges a $59 fee plus $7.70 per week that person attends. The total cost y for any number of weeks x can be given using t

lianna [129]

Firstly the equation would be y=7.7x+59
(A)The slope is 7.7 (B) and shows that there is a 7.7 charge per week the person attends.
(A)The y intercept is 59 (B) and is the initial fee that the gym charges.

8 0

2 years ago

Cos^2x+cos^2(120°+x)+cos^2(120°-x)<br>i need this asap. pls help me

o-na [289]

Answer:

$\frac{3}{2}$

Step-by-step explanation:

Using the addition formulae for cosine

cos(x ± y) = cosxcosy ∓ sinxsiny

---------------------------------------------------------------

cos(120 + x) = cos120cosx - sin120sinx

= - cos60cosx - sin60sinx

= - $\frac{1}{2}$ cosx - $\frac{\sqrt{3} }{2}$ sinx

squaring to obtain cos² (120 + x)

= $\frac{1}{4}$ cos²x + $\frac{\sqrt{3} }{2}$ sinxcosx + $\frac{3}{4}$ sin²x

--------------------------------------------------------------------

cos(120 - x) = cos120cosx + sin120sinx

= -cos60cosx + sin60sinx

= - $\frac{1}{2}$ cosx + $\frac{\sqrt{3} }{2}$ sinx

squaring to obtain cos²(120 - x)

= $\frac{1}{4}$ cos²x - $\frac{\sqrt{3} }{2}$ sinxcosx + $\frac{3}{4}$ sin²x

--------------------------------------------------------------------------

Putting it all together

cos²x + $\frac{1}{4}$ cos²x + $\frac{\sqrt{3} }{2}$ sinxcosx + $\frac{3}{4}$ sin²x + $\frac{1}{4}$ cos²x - $\frac{\sqrt{3} }{2}$ sinxcosx + $\frac{3}{4}$ sin²x

= cos²x + $\frac{1}{2}$ cos²x + $\frac{3}{2}$ sin²x

= $\frac{3}{2}$ cos²x + $\frac{3}{2}$ sin²x

= $\frac{3}{2}$ (cos²x + sin²x) = $\frac{3}{2}$

5 0

2 years ago

Pls be right will give brainliest

andreev551 [17]

Answer:

D: Yes, a reasonable estimate is around 5 · $7 = $35.

Step-by-step explanation:

None

6 0

2 years ago

I need help on number 18

zloy xaker [14]

Answer:

Volume = 35185.8 $km^{3}$

Step-by-step explanation:

Recall the formula for the volume of a cone: $Volume = \pi R^{2} \frac{h}{3}$

Where R is the radius of the cone's circular base (in your case half of 80 km,(that is 40 km)

And h stands for the height of the cone (in your case 21 km)

We replace such in the formula and calculate its final value:

$Volume = \pi 40^{2} \frac{21}{3} = \pi 1600 \frac{21}{3} = \pi 1600 (7) = 35185.83772...$

We round it to the number of decimals your problem request (let's say to one decimal) and also include the cubic units:

Volume = 35185.8 $km^{3}$

7 0

2 years ago