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2 years ago

What is the area of this parallelogram

Mathematics

1 answer:

murzikaleks [220]2 years ago

4 0

Answer:

84m^2

Step-by-step explanation:

The area of a parallelogram is calculated by multiplying height to the base

The height of the given parallelogram is 7m and the base is 12m

12 × 7 = 84

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A driver is 19 meters below the surface of the water. Use an integer to represent how far the driver will need to travel to reac

Tresset [83]

Answer:

19 metres

Step-by-step explanation:

3 0

2 years ago

Let f(x) = x - 3 and g(x) = x + 11 find f(x) times g(x) What is the answer?

notsponge [240]

f(x) *g(x) = (x-3)(x+11) = x^2 +11x -3x -33 = x^2 +8x -33

Sorry if its wrong :(

6 0

2 years ago

Select the correct answer. Which function is the inverse of ?

Artyom0805 [142]

Answer:

B. $f^{-1}(x) = \frac{x + 3}{9}$

Step-by-step explanation:

$let \space\ y = f(x)\\\\y = 9x -3\\$

• Now make x the subject of the equation:

$9x = y + 3\\\\x = \frac{y + 3}{9} \\$

• Replace x with f⁻¹(x) and y with x:

$f^{-1}(x) = \frac{x + 3}{9}$

6 0

1 year ago

Read 2 more answers

Write in y=mx+b form

DENIUS [597]

Step-by-step explanation:

b =-4 (y-intercept)

x =0

m = 0 (the line doesn't have a slope)

y = mx + c

y = 0(0) + (-4)

y = - 4

7 0

2 years ago

Find the unit vector in the direction of u = (-3,2).

DENIUS [597]

$\bf \textit{unit vector for }(a,b)\implies \left( \cfrac{a}{\sqrt{a^2+b^2}}~~,~~\cfrac{b}{\sqrt{a^2+b^2}} \right)\\\\
-------------------------------\\\\
(-3,2)\qquad \stackrel{unit~vector}{\implies }\qquad \left( \cfrac{-3}{\sqrt{(-3)^2+2^2}}~~,~~\cfrac{2}{\sqrt{(-3)^2+2^2}} \right)
\\\\\\
\left( -\cfrac{3}{\sqrt{13}}~~,~~ \cfrac{2}{\sqrt{13}}\right)\\\\
-------------------------------$

$\bf \textit{and now let's \underline{rationalize} the denominator for each}
\\\\\\
-\cfrac{3}{\sqrt{13}}\cdot \cfrac{\sqrt{13}}{\sqrt{13}}\implies -\cfrac{3\sqrt{13}}{13} \qquad \qquad \qquad \qquad \cfrac{2}{\sqrt{13}}\cdot \cfrac{\sqrt{13}}{\sqrt{13}}\implies \cfrac{2\sqrt{13}}{13}
\\\\\\
\textit{and written in \underline{ai+bj form}}\qquad -\cfrac{3\sqrt{13}}{13}i~~~~+~~~~\cfrac{2\sqrt{13}}{13}j$

7 0

2 years ago