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hjlf
3 years ago
7

benjamin is 3/4 as heavy s Ann. Siti is twice as heavy as benjamin. If Ann is 35kg, find Siti mass                      PLZZZZZZ

ZZZZZZZZ ANSWER
Mathematics
1 answer:
luda_lava [24]3 years ago
6 0
I already answered it on one of your posts with the same question, but here I'll tell you again :)

<span>Okay so first set up the equation(s) for this situation. In this case, you need two equations:
B=3/4A (In which B= Benjamin and A=Ann)
S=2B (In which S= Siti and B= Benjamin)
Now first solve for the first equation where you can plug in A for 35kg:
B=3/A
B=3/4*35
B=26.25
Now you can use that value and use it for the second equation. Plug in B with 26.25:
S=2B
S=2*26.25
S=52.5
So Siti has a mass of 52.5 kg</span>
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A particle moves along the x-axis with velocity v(t) = t2 - 1, with t measured in seconds and v(t) measured in feet per second.
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Your flight has been delayed: At Denver International Airport, 85% of recent flights have arrived on time. A sample of 14 flight
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Answer:

a. p=1.000

b. p=0.2924

c. p=0.7358

d. No

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P(X=x){n\choose x}p^x(1-p)^{n-x}

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P(X\geq 1)=1-P(X=0)\\\\=1-{12\choose 0}0.85^0(1-0.85)^{12}\\\\=1-1.297\times 10^{-10}\\\\=1.0000

Hence, the probability that all 12 flights are on time is 1.0000

b. Given that n=12, and p=0.85

-The probability that exactly 10 flights are on time is calculated as;

P(X=x)={n\choose x}p^x(1-p)^{n-x}\\\\={12\choose 10}0.85^{10}(1-0.85)^{2}\\\\=0.2924

Hence, the probability that exactly 10 flights are on time is 0.2924

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P(X=x)={n\choose x}p^x(1-p)^{n-x}\\\\P(X\geq 10)=P(X=10)+P(X=11)+P(X=12)\\\\={12\choose 10}0.85^{10}(0.15)^{2}+{12\choose 11}0.85^{11}(0.15)^{1}+{12\choose 12}0.85^{12}(0.15)^{0}\\\\=0.2924+0.3012+0.1422\\\\=0.7358

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\mu=E(X)=0.85\times 14\\\\=11.9

#We then find the probability of 11+=0.3012+0.1422=0.4434

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No. Since the probability P(X\geq 10)=0.4434 < that the expectation, 11.9, it is not unusual  for 11+ flights to be on time.

*I have used a sample size of n=12 since there are two separate n values:

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