Answer:
Step-by-step explanation:
Given a ΔLMN.
Line LN is extended to point O.
such that:
and
To find:
Solution:
Kindly refer to the attached image for the given triangle and dimensions of angles.
Let us recall the external angle property of a triangle:
The external angle of a triangle is equal to the sum of two opposite internal angles.
i.e.
Putting the value of 
in 
.
2,3,4,1, the probability is in order from greatest to least. If they asked for least to greatest then, 1,4,3,2. So use the least to greatest one.
Answer:
56.7
Step-by-step explanation:
We know
mean = sum / count, with count being the amount of papers corrected in this case. We want to find the sum of all the papers as well as the count to figure out the mean of all papers.
For Tony's papers,
mean = sum / count
50 = sum / 40
multiply both sides by 40 to isolate the sum
sum = 50 * 40 = 2000
For Alice's papers,
mean = sum / count
70 = sum / 20
multiply both sides by 20 to isolate the sum
70 * 20 = sum = 1400
The total sum of all 60 papers is equal to the sum of 40 papers + the sum of the remaining 20 papers, or 2000 + 1400 = 3400. The mean of the 60 papers is therefore
mean = sum / count
mean = 3400/60 ≈ 56.7
Answer: See the answers below.
The first equation that needs to be solve is: 10 = -16t^2 + 18
If you use the quadratic equation, you will get 0.707 seconds.
For the second equation, you need to solve 0 = -16t^2 + 18.
If you use the quadratic equation, you will get 1.061 seconds.
No, the rate of change is not constant because this is a quadratic equation.
