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Zepler [3.9K]
3 years ago
6

Help please I’ll give you 25 points

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
4 0

Answer: Choice D) y = \pm \sqrt{x+5}

The steps to finding the inverse will have us swap x and y. Afterward, we solve for y

y = x^2 - 5 \\\\x = y^2 - 5 \\\\x+5 = y^2 \\\\y^2 = x+5 \\\\y = \pm \sqrt{x+5} \\\\

------------------------------

Extra info:

The inverse relation is not a function because of the plus minus. For instance, plugging x = 4 into y = \pm \sqrt{x+5} leads to y = -3 and y = 3 simultaneously. You would have to apply a domain restriction on y = x^2-5 to make it a one-to-one function, to make the inverse a function. One possible domain restriction is x > 0 which would lead to the inverse function y = \sqrt{x+5}

You might be interested in
<img src="https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%3D%20%20-%205x" id="TexFormula1" title=" {x}^{2} = - 5x" alt=" {x}^{2
aliina [53]

Answer:

x(x + 5) = 0

Step-by-step explanation:

x² = - 5x

x² + 5x = 0

<em><u>x(x + 5) = 0</u></em>

<em><u>hope it's helpful</u></em>

3 0
3 years ago
Read 2 more answers
Solve the triangle. Round your answers to the nearest tenth.
Tresset [83]

Answer:

<B = 47°

<C = 28°

b = AC = 28.0

Step-by-step explanation:

Given:

∆ABC

AB = c = 18

BC = a = 37

<A = 105°

Required:

Length of AC = b

measure of angle B and angle C

SOLUTION:

==>Use the sine rule, sin A/a = sinC/c to find the angle of C:

SinA = sin(105) = 0.9659

a = 37

sinC = ?

c = 18

0.9659/37 = sinC/18

Cross multiply

0.9659*18 = 37*sinC

17.3862 = 37*sinC

Divide both sides by 37

17.3862/37 = sinC

0.4699 = sinC

sinC = 0.4699

C = Sin-¹(0.4699)

C = 28.0° (nearest tenth)

==>Find angle B using sum of angles in a triangle:

Angle B = 180 - (105+28)

Angle B = 180 - 133

Angle B = 47°

==>Find length of b using sine rule, b/sinB = c/sinC:

SinC = sin(28) = 0.4695

SinB = sin(47) = 0.7314

c = 18

b = ?

b/0.7314 = 18/0.4695

Cross multiply

b*0.4695 = 18*0.7314

b*0.4695 = 13.1652

Divide both sides by 0.4695

b = 13.1652/0.4695

b = 28.0 (nearest tenth)

6 0
3 years ago
The figure below shows a straight line AB intersected by another straight line t:
BaLLatris [955]

When two straight lines intersect, the pairs of nonadjacent angles in opposite posi-tions are known as vertical angles.

If a segment AB is intersected by a transversal labeled t, then ∠1 and ∠3 and ∠2 and ∠4 are vertically angles formed by the transversal t on the segment AB.

Angles ∠1 and ∠2 can be described as adjacent and supplementary angles, so

m\angle 1+m\angle 2=180^{\circ}.

Angles ∠3 and ∠2 can be also described as adjacent and supplementary angles, so

m\angle 3+m\angle 2=180^{\circ}.

Subtract from the first equation the second equation:

m\angle 1+m\angle 2-(m\angle 3+m\angle 2)=180^{\circ}-180^{\circ},\\ m\angle 1-m\angle 3=0,\\ m\angle 1=m\angle 3.

Similarly you can prove that m\angle 2=m\angle 4.

4 0
3 years ago
Brett has a $30 online gift certificate. He plans to buy as many books as he can. The cost of each book is $4. There is also a s
kkurt [141]

Answer:

7 books

Step-by-step explanation:

make an equation

x = # of books each book is $4 so its 4x

the shipping fee no matter how many books he buys will be $2 so it's just 2

the equation looks like this:

4x + 2 = 30

we set equal to 30 cuz he can't spend more than $30

solve for x

4x = 30 -2

4x = 28

x = 7

Brett can buy no more than 7 books.

7 0
3 years ago
Enter the values of h and I so that y=x2+6x+10 is in vertex form<br> Y=(x+__)^2+___
DiKsa [7]

Use\ (a+b)^2=a^2+2ab+b^2\qquad(*)\\\\y=x^2+6x+10=x^2+2(x)(3)+10=\underbrace{x^2+2(x)(3)+3^2}_{(*)}-3^2+10\\\\=(x+3)^2-9+10=(x+3)^2+1\\\\Answer:\ \boxed{y=(x+3)^2+1}

3 0
3 years ago
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